AC自己主动机的模板题。因为输入的字符串中的字符不保证全为小写字母。所以范围应该在130之前,而前31位字符是不可能出如今字符串的(不懂得查下ACSII表即可了)。所以仅仅须要开的结点数组大小为130足够了。假设开256就会内存超限。
11908775 | 2014-10-19 10:45:38 | Accepted | 2896 | 250MS | 29596K | 2760 B | G++ | KinderRiven |
输入仅仅有一组,所以不用操心超时的问题。
#include<queue> #include<cstdio> #include<vector> #include<cstring> #include<algorithm> using namespace std; const int maxn = 111111; const int max_size = 130; const int maxd = 222; vector<int>G[1111]; struct Trie{ int next[maxn][max_size]; int fail[maxn]; int val[maxn]; int sz; int root; int index(char e){ return e - 31; } void init(){ sz = 0; root = newnode(); } int newnode(){ val[sz] = 0; memset(next[sz],-1,sizeof(next[sz])); sz ++; return sz - 1; } void insert(char *str,int pos){ int L = strlen(str); int u = root; for(int i = 0; i < L; i++){ int e = index(str[i]); if(next[u][e] == -1) next[u][e] = newnode(); u = next[u][e]; } val[u] = pos; //printf("%d %d ",u,pos); } void build(){ //建立失配边 fail[root] = root; queue<int>q; for(int i = 0; i < max_size; i++){ if(next[root][i] == -1) next[root][i] = root; else{ fail[next[root][i]] = root; q.push(next[root][i]); } } while(!q.empty()){ int now = q.front(); q.pop(); for(int i = 0; i < max_size; i++){ if(next[now][i] == -1) next[now][i] = next[fail[now]][i]; else{ fail[next[now][i]] = next[fail[now]][i]; q.push(next[now][i]); } } } } void count(char *str,int pos){ int L = strlen(str); int u = root; for(int i = 0; i < L; i++){ int e = index(str[i]); u = next[u][e]; int temp = u; while(temp != root){ if(val[temp] != 0) G[pos].push_back(val[temp]); temp = fail[temp]; } } return; } }; Trie ac; int main(){ int n,m; ac.init(); scanf("%d",&n); for(int i = 1; i <= n; i++){ char str[maxd]; scanf("%s",str); ac.insert(str,i); } //printf("%d ",ac.sz); ac.build(); scanf("%d",&m); for(int i = 1; i <= m; i++){ char str[maxn]; scanf("%s",str); ac.count(str,i); } int cnt = 0; for(int i = 1; i <= m; i++)if(G[i].size()){ sort(G[i].begin(),G[i].end()); cnt ++; printf("web %d:",i); for(int j = 0; j < G[i].size(); j++) printf(" %d",G[i][j]); printf(" "); } printf("total: %d ",cnt); }