• LeetCode: Surrounded Regions


    看了网上答案,dfs

     1 class Solution {
     2 public:
     3     void dfs(vector<vector<char>> &board, int x, int y) {
     4         if (x < 0 || x >= board.size() || y < 0 || y >= board.size()) return;
     5         if (board[x][y] == 'O') {
     6             board[x][y] = '#';
     7             dfs(board, x-1, y);
     8             dfs(board, x+1, y);
     9             dfs(board, x, y-1);
    10             dfs(board, x, y+1);
    11         }
    12     }
    13     void solve(vector<vector<char>> &board) {
    14         // Start typing your C/C++ solution below
    15         // DO NOT write int main() function
    16         if (!board.size()) return;
    17         int n = board[0].size();
    18         for (int i = 1; i < n-1; i++) {
    19             dfs(board, i, 0);
    20             dfs(board, i, n-1);
    21         }
    22         for (int i = 0; i < n; i++) {
    23             dfs(board, 0, i);
    24             dfs(board, n-1, i);
    25         }
    26         for (int i = 0; i < n; i++) {
    27             for (int j = 0; j < n; j++) {
    28                 if (board[i][j] == 'O') board[i][j] = 'X';
    29                 if (board[i][j] == '#') board[i][j] = 'O';
    30             }
    31         }
    32     }
    33 };

     自己写的bfs代码:

     1 class Solution {
     2 public:
     3     struct node {
     4         int x, y;
     5         node(int a, int b) : x(a), y(b) { }
     6         node() : x(0), y(0) { }
     7     };
     8     void solve(vector<vector<char>> &board) {
     9         if (board.size() <= 2 || board[0].size() <= 2) return;
    10         int m = board.size();
    11         int n = board[0].size();
    12         vector<vector<bool> > visit(m, vector<bool>(n));
    13         int dir[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
    14         queue<node> S;
    15         for (int i = 1; i < m-1; i++) {
    16             if (board[i][0] == 'O') S.push(node(i, 0));
    17             if (board[i][n-1] == 'O') S.push(node(i, n-1));
    18         }
    19         for (int i = 1; i < n-1; i++) {
    20             if (board[0][i] == 'O') S.push(node(0, i));
    21             if (board[m-1][i] == 'O') S.push(node(m-1, i));
    22         }
    23         while (!S.empty()) {
    24             node front = S.front();
    25             S.pop();
    26             for (int i = 0; i < 4; i++) {
    27                 int xx = front.x + dir[i][0];
    28                 int yy = front.y + dir[i][1];
    29                 if (xx <= 0 || xx >= m-1 || yy <= 0 || yy >= n-1 || board[xx][yy] == 'X' || visit[xx][yy]) continue;
    30                 S.push(node(xx, yy));
    31                 visit[xx][yy] = true;
    32             }
    33         }
    34         for (int i = 1; i < m-1; i++) {
    35             for (int j = 1; j < n-1; j++) {
    36                 if (board[i][j] == 'X') continue;
    37                 else if (!visit[i][j]) board[i][j] = 'X';
    38             }
    39         }
    40     }
    41 };

     C#

     1 public class Solution {
     2     public class node {
     3         public int x;
     4         public int y;
     5         public node() { x = 0; y = 0; }
     6         public node (int a, int b) { x = a; y = b; }
     7     }
     8     public void Solve(char[,] board) {
     9         int m = board.GetLength(0);
    10         int n = board.GetLength(1);
    11         if (m <= 2 || n <= 2) return;
    12         bool[,] visit = new bool[m, n];
    13         int[,] dir = new int[4, 2] {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
    14         Queue<node> S = new Queue<node>();
    15         for (int i = 1; i < m-1; i++) {
    16             if (board[i, 0] == 'O') S.Enqueue(new node(i, 0));
    17             if (board[i, n-1] == 'O') S.Enqueue(new node(i, n-1));
    18         }
    19         for (int i = 1; i < n-1; i++) {
    20             if (board[0, i] == 'O') S.Enqueue(new node(0, i));
    21             if (board[m-1, i] == 'O') S.Enqueue(new node(m-1, i));
    22         }
    23         while (S.Count > 0) {
    24             node peek = S.Peek();
    25             S.Dequeue();
    26             for (int i = 0; i < 4; i++) {
    27                 int xx = peek.x + dir[i, 0];
    28                 int yy = peek.y + dir[i, 1];
    29                 if (xx <= 0 || xx >= m-1 || yy <= 0 || yy >= n-1 || board[xx, yy] == 'X' || visit[xx, yy]) continue;
    30                 S.Enqueue(new node(xx, yy));
    31                 visit[xx, yy] = true;
    32             }
    33         }
    34         for (int i = 1; i < m-1; i++) {
    35             for (int j = 1; j < n-1; j++) {
    36                 if (board[i, j] == 'X') continue;
    37                 else if (!visit[i, j]) board[i, j] = 'X';
    38             }
    39         }
    40     }
    41 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3034833.html
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