• LeetCode: Remove Nth Node From End of List


    一次过

     1 /**
     2  * Definition for singly-linked list.
     3  * struct ListNode {
     4  *     int val;
     5  *     ListNode *next;
     6  *     ListNode(int x) : val(x), next(NULL) {}
     7  * };
     8  */
     9 class Solution {
    10 public:
    11     ListNode *removeNthFromEnd(ListNode *head, int n) {
    12         // Start typing your C/C++ solution below
    13         // DO NOT write int main() function
    14         vector<ListNode *> S;
    15         ListNode *tmp = head;
    16         while (tmp) {
    17             S.push_back(tmp);
    18             tmp = tmp->next;
    19         }
    20         S.push_back(NULL);
    21         int size = S.size();
    22         if (size < n+2) return head->next;
    23         S[size-n-2]->next = S[size-n];
    24         return head;
    25     }
    26 };

     C#

     1 /**
     2  * Definition for singly-linked list.
     3  * public class ListNode {
     4  *     public int val;
     5  *     public ListNode next;
     6  *     public ListNode(int x) { val = x; }
     7  * }
     8  */
     9 public class Solution {
    10     public ListNode RemoveNthFromEnd(ListNode head, int n) {
    11         List<ListNode> S = new List<ListNode>();
    12         ListNode tmp = head;
    13         while (tmp != null) {
    14             S.Add(tmp);
    15             tmp = tmp.next;
    16         }
    17         S.Add(null);
    18         int c = S.Count;
    19         if (c < n + 2) return head.next;
    20         S[c - n - 2].next = S[c - n];
    21         return head;
    22     }
    23 }
    View Code
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  • 原文地址:https://www.cnblogs.com/yingzhongwen/p/3031923.html
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