• oracle 知识


    1.查询索引数量

    select table_name, count(*) cnt
    from user_indexes where index_type='NORMAL'
    group by table_name
    having count(*) >= 1
    order by cnt desc ;

    2.查询外键未建建索引的情况。

    select table_name,
    constraint_name,
    cname1 || nvl2(cname2, ',' || cname2, null) ||
    nvl2(cname3, ',' || cname3, null) ||
    nvl2(cname4, ',' || cname4, null) ||
    nvl2(cname5, ',' || cname5, null) ||
    nvl2(cname6, ',' || cname6, null) ||
    nvl2(cname7, ',' || cname7, null) ||
    nvl2(cname8, ',' || cname8, null) columns
    from (select b.table_name,
    b.constraint_name,
    max(decode(position, 1, column_name, null)) cname1,
    max(decode(position, 2, column_name, null)) cname2,
    max(decode(position, 3, column_name, null)) cname3,
    max(decode(position, 4, column_name, null)) cname4,
    max(decode(position, 5, column_name, null)) cname5,
    max(decode(position, 6, column_name, null)) cname6,
    max(decode(position, 7, column_name, null)) cname7,
    max(decode(position, 8, column_name, null)) cname8,
    count(*) col_cnt
    from (select substr(table_name, 1, 30) table_name,
    substr(constraint_name, 1, 30) constraint_name,
    substr(column_name, 1, 30) column_name,
    position
    from user_cons_columns) a,
    user_constraints b
    where a.constraint_name = b.constraint_name
    and b.constraint_type = 'R'
    group by b.table_name, b.constraint_name) cons
    where col_cnt > ALL
    (select count(*)
    from user_ind_columns i
    where i.table_name = cons.table_name
    and i.column_name in (cname1, cname2, cname3, cname4, cname5,
    cname6, cname7, cname8)
    and i.column_position <= cons.col_cnt
    group by i.index_name);
    

    3.查询哪些组合索引组合列超过4个的

    select table_name, index_name, count(*)
      from user_ind_columns
     group by table_name, index_name
    having count(*) >= 4
     order by count(*) desc;

    4.查询大表创建索引

    select segment_name, bytes/1024/1024/1024 "GB", blocks, tablespace_name
      from user_segments
     where segment_type = 'TABLE'
       and segment_name not in (select table_name from user_indexes)
       and bytes / 1024 / 1024 / 1024 >= 2
     order by GB desc;

    5.查询失效的索引

    select t.index_name,
           t.table_name,
           blevel,
           t.num_rows,
           t.leaf_blocks,
           t.distinct_keys
      from user_indexes t
    where status = 'UNUSABLE' ;

    6.查询分区失效索引

    select t1.blevel,
           t1.leaf_blocks,
           t1.INDEX_NAME,
           t2.table_name,
           t1.PARTITION_NAME,
           t1.STATUS
      from user_ind_partitions t1, user_indexes t2
    where t1.index_name = t2.index_name
       and t1.STATUS = 'UNUSABLE';

     7.查询单列索引和组合索引存在交叉的情况。

     单列索引和组合索引使用了相同的字段。

    select table_name, trunc(count(distinct(column_name)) / count(*),2) cross_idx_rate
      from user_ind_columns
     group by table_name
    having count(distinct(column_name)) / count(*) < 1
    order by cross_idx_rate desc;

     8.查询索引高度较高的索引。

    select table_name,
           index_name,
           blevel,
           leaf_blocks,
           num_rows,
           last_analyzed,
           degree,
           status
      from user_indexes
      where  blevel>=1;

     9.普通索引(从未收集过统计信息或者是最近10天内未收集过统计信息的表)

    select index_name, table_name, last_analyzed, num_rows, temporary, status
      from user_indexes
     where status <> 'N/A'
       and (last_analyzed is null or last_analyzed < sysdate - 10);

    10.分区索引(从未收集过统计信息或者是最近10天内未收集过统计信息的分区)

    select t2.table_name,
           t1.INDEX_NAME,
           t1.PARTITION_NAME,
           t1.last_analyzed,
           t1.blevel,
           t1.leaf_blocks,             
           t1.STATUS
      from user_ind_partitions t1, user_indexes t2
    where t1.index_name = t2.index_name
      and (t1.last_analyzed is null or t1.last_analyzed < sysdate - 10);

    11.外键约束失效。

    SELECT TABLE_NAME,
           CONSTRAINT_NAME,
           STATUS,
           CONSTRAINT_TYPE,
           R_CONSTRAINT_NAME
      FROM USER_CONSTRAINTS
     WHERE STATUS='DISABLED';
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  • 原文地址:https://www.cnblogs.com/yg_zhang/p/3830575.html
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