既然是模板, 那就直接贴代码?
两种思路
1.迪杰斯特拉
#include <cstdio> #include <cstring> #include <iostream> using namespace std; const int N = 500007; int head[N], cnt, n, m, s; long long dis[N]; bool vis[N]; struct node { int next, to; long long w; }e[N]; void add(int x, int y, long long z) { e[++cnt].next = head[x]; e[cnt].to = y; e[cnt].w = z; head[x] = cnt; } void dijkstra(int s) { for(int i = 1; i <= n; i++) dis[i] = 2147483647; dis[s] = 0; for(int i = 1; i <= n; i++) { int k = 1, maxn = 2147483647; for(int j = 1; j <= n; j++) if(!vis[j] && dis[j] <= maxn) k = j, maxn = dis[j]; vis[k] = 1; for(int j = head[k]; j; j = e[j].next) if(dis[e[j].to] > dis[k] + e[j].w) dis[e[j].to] = dis[k] + e[j].w; } } int main () { scanf("%d%d%d", &n, &m, &s); for(int i = 1; i <= m; i++) { int x, y; long long z; scanf("%d%d%lld", &x, &y, &z); add(x, y, z); } dijkstra(s); for(int i = 1; i <= n; i++) printf("%lld ", dis[i]); return 0; }
2.spfa
#include <iostream> #include <cstdio> #include <queue> #define N 500005 #define inf 2147483647 using namespace std; int n, m, s, cnt; int dis[N], vis[N], head[N]; struct node { int next, to, w; }tr[N]; void add (int x, int y, int z) { tr[++cnt].to = y; tr[cnt].next = head[x]; tr[cnt].w = z; head[x] = cnt; } void spfa () { queue<int> q; for (int i = 1; i <= n; i++) dis[i] = inf; vis[s] = 1; q.push(s); dis[s] = 0; while (!q.empty()) { int he = q.front(); q.pop(); vis[he] = 0; for (int i = head[he]; i ;i = tr[i].next) { if (dis[tr[i].to] > dis[he] + tr[i].w) { dis[tr[i].to] = dis[he] + tr[i].w; if (!vis[tr[i].to]) { vis[tr[i].to] = 1; q.push(tr[i].to); } } } } } int main () { scanf ("%d%d%d", &n, &m, &s); for (int i = 1; i <= m; i++) { int a, b, c; scanf ("%d%d%d", &a, &b, &c); add (a, b, c); } spfa (); for (int i = 1; i <= n; i++) if (s == i) printf ("0 "); else printf ("%d ", dis[i]); return 0; }
add:2019.8.15
增加堆优化后的迪杰斯特拉算法;
用来切标准版
#include <queue> #include <cstdio> #include <cstring> #include <iostream> using namespace std; const int N = 1010001; int n, m, s, cnt, head[N], dis[N]; bool vis[N]; struct node{ int next, to, w; }e[N]; int read() { int s = 0, w = 1; char ch = getchar(); while(!isdigit(ch)){if(ch == '-') w = -1;ch = getchar();} while(isdigit(ch)){s = s * 10 + ch - '0';ch = getchar();} return s * w; } void add(int x, int y, int z) { e[++cnt].next = head[x]; e[cnt].to = y; e[cnt].w = z; head[x] = cnt; } struct Node { int u, v; bool operator<(const Node &b) const { return u > b.u; } }; void dijikstra(int s) { priority_queue <Node> q; memset(dis, 0x3f3f3f3f, sizeof(dis)); dis[s] = 0; Node o; o.u = 0; o.v = s; q.push(o); while(!q.empty()) { int u = q.top().v; int d = q.top().u; q.pop(); if(d != dis[u])continue; for(int i = head[u]; i; i = e[i].next) { int v = e[i].to; int w = e[i].w; if(dis[v] > dis[u] + w) { dis[v] = dis[u] + w; Node p; p.u = dis[v], p.v = v; q.push(p); } } } } int main () { n = read(); m = read(); s = read(); while(m--) { int x, y, z; x = read(); y = read(); z = read(); add (x, y, z); } dijikstra(s); for(int i = 1; i <= n; i++) printf("%d ", dis[i]); return 0; }