• sql 时间查询 /sql中判断更新或者插入/查询一年所有双休日


    if exists(SELECT *FROM [DBPersonnel].[dbo].[TB証明書] where [社員番号]='001')
      update [DBPersonnel].[dbo].[TB証明書] set [身分証明書]='11' where [社員番号]='001'
    else
     INSERT INTO [DBPersonnel].[dbo].[TB証明書] ([社員番号],[身分証明書],[卒業証書])
         VALUES ('001','sssss','ssssss')
    
    
    
    取得本月天数 
    select datediff(day,cast(month(GetDate()) as varchar)+'-'+cast(month(GetDate()) as varchar)+'-15' ,cast(month(GetDate()) as varchar)+'-'+cast(month(GetDate())+1 as varchar)+'-15') 
    
    
    一个季度多少天 
     
     
      declare @m tinyint,@time smalldatetime 
    select @m=month(getdate()) 
    select @m=case when @m between 1 and 3 then 1 
    when @m between 4 and 6 then 4 
    when @m between 7 and 9 then 7 
    else 10 end 
    select @time=datename(year,getdate())+'-'+convert(varchar(10),@m)+'-01' 
    select datediff(day,@time,dateadd(mm,3,@time))
    
    
    
    判断是否闰年:
    
      SELECT case day(dateadd(mm, 2, dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)))) when 28 then '平年' else '闰年' end 
    或者 
    select case datediff(day,datename(year,getdate())+'-02-01',dateadd(mm,1,datename(year,getdate())+'-02-01')) 
    when 28 then '平年' else '闰年' end 


    所有休息日

    DECLARE @Work_LegalHoliday TABLE
    (
    ID VARCHAR(36) ,
    DateTimeName DATETIME ,
    WeekName VARCHAR(50) ,
    IsLegalHoliday INT ,
    Remark NVARCHAR(MAX)
    )


    DECLARE @Year INT

    SET @Year = 2015
    --
    ;
    WITH tbSource
    AS ( SELECT CAST(RTRIM(@Year) + '-01-01' AS DATETIME) DateTimeName
    UNION ALL
    SELECT DATEADD(dd, 1, DateTimeName)
    FROM tbSource
    WHERE DATEPART(yy, DATEADD(dd, 1, DateTimeName)) = @Year
    )
    INSERT @Work_LegalHoliday
    SELECT NEWID() ,
    CONVERT(VARCHAR(10), DateTimeName, 121) ,
    DATENAME(WEEKDAY, DateTimeName) ,
    0 ,--不是法定假日
    '' AS Remark
    FROM tbSource a
    WHERE DATEPART(WEEKDAY, a.DateTimeName) = 1
    OR DATEPART(WEEKDAY, a.DateTimeName) = 7
    EXCEPT
    SELECT NEWID() ,
    CONVERT(VARCHAR(10), DateTimeName, 121) ,
    DATENAME(WEEKDAY, DateTimeName) ,
    0 ,
    '' AS Remark
    FROM @Work_LegalHoliday
    OPTION ( MAXRECURSION 0 )
    SELECT *
    FROM @Work_LegalHoliday

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  • 原文地址:https://www.cnblogs.com/yangpeng-jingjing/p/5141578.html
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