表:order ,字段:orderid, userid, isPaid, price, paidTime
表:user,字段: userid, sex, birth
1.统计不同月份下单人数
select month(date_format(paidtime, '%Y-%m-%d')), count(distinct userid)
from order
where isPaid = '已支付'
group by month(date_format(paidtime, '%Y-%m-%d'));
2.统计3月份回购率和复购率
2.1 3月份复购率
复购率:3月份中购买两次以上的人数占3月份总购买人数的比例
3月份购买人数
select userid, count(userid) as count_userid
from order
where ispaid = '已支付'
and month(date_format(paidtime, '%Y-%m-%d')) = 3
group by userid;
复购率 =3月份购买两次以上的人数/ 对3月份复购人数统计去重
select count(t.userid) as 购买人数, count(if(t.count_userid>1, 1, null)) as '复购人数',
count(if(t.count_userid>1, 1, null)) / count(t.userid) as '复购率'
from (select userid, count(userid) as count_userid
from order
where ispaid = '已支付'
and month(date_format(paidtime, '%Y-%m-%d')) = 3
group by userid
) t
2.2 用户回购率
运用子查询,筛选出第二个月有购买记录的情况,然后进行count
select t1.m, count(t1.userid), count(t2.userid)
from (select userid), date_format(paidtime, '%Y-%m-01') as m
from order
where ispaid = '已支付'
group by userid, date_format(paidtime, '%Y-%m-01')
) as t1
left join
(select userid, date_format(paidtime, '%Y-%m-01') as m
from order
where ispaid = '已支付'
group by userid, date_format(paidtime, '%Y-%m-01')
) as t2
on t1.userid = t2.userid and t1.m = date_sub(t2.m, INTERVAL 1 month)
group by t1.m
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统计第一次和最后一次消费间隔多久
select userid, datediff(max(paidtime), min(paidtime)) from order where ispaid = '已支付' group by userid having count(1) > 1