Given a binary search tree and the lowest and highest boundaries as L
and R
, trim the tree so that all its elements lies in [L, R]
(R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary search tree.
Example 1:
Input: 1 / 0 2 L = 1 R = 2 Output: 1 2
Example 2:
Input: 3 / 0 4 2 / 1 L = 1 R = 3 Output: 3 / 2 / 1
思路:递归(Recursion)
1.从根节点root开始,若当前节点值小于L,则砍掉左子树,保留右子树,对右子树进行剪枝;
2.若当前节点值大于R,则砍掉右子树,保留左子树,对左子树进行剪枝;
3.若当前节点值位于[L,R]之间,则递归,分别对左、右子树进行剪枝;
# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def trimBST(self, root, L, R): """ :type root: TreeNode :type L: int :type R: int :rtype: TreeNode """ if not root: return None if root.val < L: return self.trimBST(root.right, L, R) if root.val > R: return self.trimBST(root.left, L, R) root.left = self.trimBST(root.left, L, R) root.right = self.trimBST(root.right, L, R) return root