• 19.2.3 [LeetCode 37] Sudoku Solver


    Write a program to solve a Sudoku puzzle by filling the empty cells.

    A sudoku solution must satisfy all of the following rules:

    1. Each of the digits 1-9 must occur exactly once in each row.
    2. Each of the digits 1-9 must occur exactly once in each column.
    3. Each of the the digits 1-9 must occur exactly once in each of the 9 3x3sub-boxes of the grid.

    Empty cells are indicated by the character '.'.


    A sudoku puzzle...


    ...and its solution numbers marked in red.

    Note:

      • The given board contain only digits 1-9 and the character '.'.
      • You may assume that the given Sudoku puzzle will have a single unique solution.
      • The given board size is always 9x9.
     1 class Solution {
     2 public:
     3     bool solvefromone(int x, int y, vector<vector<char>>&board) {
     4         bool used[10] = { false };
     5         for (int i = 0; i < 9; i++) {
     6             if (board[x][i] != '.')
     7                 used[board[x][i] - '0'] = true;
     8             if (board[i][y] != '.')
     9                 used[board[i][y] - '0'] = true;
    10         }
    11         int xs = x / 3 * 3, xe = xs + 2, ys = y / 3 * 3, ye = ys + 2;
    12         for (int i = xs; i <= xe; i++)
    13             for (int j = ys; j <= ye; j++)
    14                 if (board[i][j] != '.')
    15                     used[board[i][j] - '0'] = true;
    16         int nextx=x, nexty=y;
    17         for(int i=y+1;i<9;i++)
    18             if (board[x][i] == '.') {
    19                 nextx = x; nexty = i;
    20                 break;
    21             }
    22         if (nexty == y) {
    23             for (int i = x + 1; i < 9; i++) {
    24                 for (int j = 0; j < 9; j++) {
    25                     if (board[i][j] == '.') {
    26                         nextx = i; nexty = j;
    27                         break;
    28                     }
    29                 }
    30                 if (nextx != x)break;
    31             }
    32         }
    33         for(int i=1;i<=9;i++)
    34             if (!used[i]) {
    35                 board[x][y] = i + '0';
    36                 if (nextx == x && nexty == y)
    37                     return true;
    38                 if (solvefromone(nextx, nexty, board))
    39                     return true;
    40             }
    41         board[x][y] = '.';
    42         return false;
    43     }
    44     void solveSudoku(vector<vector<char>>& board) {
    45         for (int i = 0; i < 9; i++)
    46             for (int j = 0; j < 9; j++)
    47                 if (board[i][j] == '.')
    48                     solvefromone(i, j, board);
    49     }
    50 };
    View Code

    暴力深搜,手误WA得有点不爽

    好冷啊

    孤单弱小无助

  • 相关阅读:
    zabbix api
    cassandra学习笔记
    loki grafana
    logstash配置 filebeat配置
    k8s prometheus api
    51cto 先超Prometheus+Grafana监控告警系统实战
    51cto 张岩峰 Prometheus企业级监控系统:零基础入门
    imooc 使用Prometheus实践基于Spring Boot监控告警体系 笔记
    python3 django migrate
    python3虚拟环境
  • 原文地址:https://www.cnblogs.com/yalphait/p/10350458.html
Copyright © 2020-2023  润新知