剑指offer python版 某一路径和为某值

from collections import deque


class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None


class Tree(object):
    def __init__(self):
        self.root = None

    def construct_tree(self, values=None):
        if not values:
            return None
        self.root = TreeNode(values[0])
        queue = deque([self.root])
        leng = len(values)
        nums = 1
        while nums < leng:
            node = queue.popleft()
            if node:
                node.left = TreeNode(values[nums]) if values[nums] else None
                queue.append(node.left)
                if nums + 1 < leng:
                    node.right = TreeNode(values[nums + 1]) if values[nums + 1] else None
                    queue.append(node.right)
                    nums += 1
                nums += 1


def find_path(tree, num):
    ret = []
    if not tree:
        return ret
    path = [tree]
    sums = [tree.val]

    def dfs(tree):
        if tree.left:
            path.append(tree.left)
            sums.append(sums[-1]+tree.left.val)
            dfs(tree.left)
        if tree.right:
            path.append(tree.right)
            sums.append(sums[-1] + tree.right.val)
            dfs(tree.right)
        if not tree.left and not tree.right:
            if sums[-1] == num:
                ret.append([p.val for p in path])
        path.pop()
        sums.pop()

    dfs(tree)
    return ret


if __name__ == '__main__':
    t = Tree()
    t.construct_tree([1, 3, 6, 4, 3, 1, 1])
print find_path(t.root, 8)