剑指offer python版 旋转数组的最小数字

def aa(nums):
    if not nums:
        return False
    left,right=0,len(nums)-1
    while nums[left]>=nums[right]:
        if right-left==1:
            return nums[right]
        
        mid=int((left+right)/2)
        if nums[left]==nums[mid]==nums[right]:
            return min(nums)
        
        if nums[left]>nums[mid]:
            right=mid
        if nums[right]<nums[mid]:
            left=mid
            
    return nums[right]

print(aa([4,5,1,2,3]))