• HDU 1561 The more, The Better (树形DP)


    http://acm.hdu.edu.cn/showproblem.php?pid=1561

    数组开小了越界,查了好久才查出来。。。GCC太能容忍错误了。。。坑!!!

    题意:

    给你一棵树,选中某一个节点花费1,得到它的价值,而且必须选中父节点才能选中子节点,问:在花费m下,最大价值为多少?

    最基本的树形DP,和前面的几道题一样

    dp[s][k]表示选中s节点,总花费k时的最大价值

    状态转移:

    for (int k = m; k >= 2; k--)
                for (int j = 1; j < k; j++)
                    dp[s][k] = max(dp[s][k], dp[s][k - j] + dp[v][j]);
      1 #pragma comment(linker, "/STACK:102400000,102400000")
      2 #include <cstdio>
      3 #include <iostream>
      4 #include <cstring>
      5 #include <string>
      6 #include <cmath>
      7 #include <set>
      8 #include <list>
      9 #include <map>
     10 #include <iterator>
     11 #include <cstdlib>
     12 #include <vector>
     13 #include <queue>
     14 #include <stack>
     15 #include <algorithm>
     16 #include <functional>
     17 using namespace std;
     18 typedef long long LL;
     19 #define ROUND(x) round(x)
     20 #define FLOOR(x) floor(x)
     21 #define CEIL(x) ceil(x)
     22 const int maxn = 210;
     23 const int maxm = 410;
     24 const int inf = 0x3f3f3f3f;
     25 const LL inf64 = 0x3f3f3f3f3f3f3f3fLL;
     26 const double INF = 1e30;
     27 const double eps = 1e-6;
     28 const int P[4] = {0, 0, -1, 1};
     29 const int Q[4] = {1, -1, 0, 0};
     30 const int PP[8] = { -1, -1, -1, 0, 0, 1, 1, 1};
     31 const int QQ[8] = { -1, 0, 1, -1, 1, -1, 0, 1};
     32 
     33 int n, m;
     34 int dp[maxn][maxn];
     35 struct Edge
     36 {
     37     int u, v;
     38     int next;
     39 } edge[maxm];
     40 int en;
     41 int head[maxn];
     42 bool vis[maxn];
     43 int node[maxn];
     44 void addsubedge(int u, int v)
     45 {
     46     edge[en].u = u;
     47     edge[en].v = v;
     48     edge[en].next = head[u];
     49     head[u] = en++;
     50 }
     51 void addedge(int u, int v)
     52 {
     53     addsubedge(u, v);
     54     //addsubedge(v, u);
     55 }
     56 void init()
     57 {
     58     memset(head, -1, sizeof(head));
     59     memset(dp, 0, sizeof(dp));
     60     en = 0;
     61     memset(node, 0, sizeof(node));
     62 }
     63 void input()
     64 {
     65     int u, w;
     66     for (int i = 1; i <= n; i++)
     67     {
     68         scanf("%d%d", &u, &w);
     69         node[i] = w;
     70         addedge(u, i);
     71     }
     72 }
     73 void dfs(int s)
     74 {
     75     //vis[s] = 1;
     76     dp[s][1] = node[s];
     77     // cout << "dfs s: " << s << endl;
     78     //cout<<"dp[s][1]: "<<s<<" "<<dp[s][1]<<endl;
     79     for (int i = head[s]; i != -1; i = edge[i].next)
     80     {
     81         int v = edge[i].v;
     82         //if (!vis[v]) dfs(v);
     83         dfs(v);
     84         for (int k = m; k >= 2; k--)
     85             for (int j = 1; j < k; j++)
     86                 dp[s][k] = max(dp[s][k], dp[s][k - j] + dp[v][j]);
     87     }
     88 }
     89 void debug()
     90 {
     91     for (int i = 0; i <= n; i++) cout << head[i] << " ";
     92     cout << endl;
     93     for (int i = 0; i <= n; i++)
     94     {
     95         for (int j = 0; j <= m; j++) cout << dp[i][j] << '	';
     96         cout << endl;
     97     }
     98 }
     99 void solve()
    100 {
    101     node[0] = 0;
    102     dfs(0);
    103 }
    104 void output()
    105 {
    106     printf("%d
    ", dp[0][m]);
    107 }
    108 int main()
    109 {
    110     // std::ios_base::sync_with_stdio(false);
    111 #ifndef ONLINE_JUDGE
    112     freopen("in.cpp", "r", stdin);
    113 #endif
    114 
    115     while (~scanf("%d%d", &n, &m))
    116     {
    117         if (!n && !m) return 0;
    118         m++;
    119         init();
    120         input();
    121         solve();
    122         // debug();
    123         output();
    124     }
    125     return 0;
    126 }
    View Code
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  • 原文地址:https://www.cnblogs.com/xysmlx/p/3536152.html
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