leetCode:Integer to Roman

题目：

Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

解题：

public class Solution {
    public String intToRoman(int num) {
        String result = "";
        int[] integer = {1000,900,500,400,100,90,50,40,10,9,5,4,1};
        String[] roman = {"M","CM","D","CD","C","XC","L","XL","X","IX","V","IV","I"};
        for(int i = 0;num!=0; i++){
            while(num >= integer[i]){
                    result+=roman[i];
                    num-= integer[i];
               
            }
        }
        return result;
    }
}

　　

想了半天的辣鸡代码：

import java.util.List;
import java.util.ArrayList;

public class Solution {
    public String intToRoman(int num) {
        
        List<Object> list = new ArrayList<Object>();
        list = count(num);
        return list.toString();
        
    }
    
    public List<Object> count(int num){
        List<Object> list = new ArrayList<Object>();
        int m = 1000,w = 500 ;
        for(int i = 0; w>0||m>0;){
            if(num/m > 0){
                for(int j = 0; j < num/m; j++)
                    list.add(choose(m));
                num = num % m;
                m = m/10;
                continue;
            }
            else if(num/w > 0){
                for(int j = 0; j < num/w; j++)
                    list.add(choose(w));
                num = num % w;
                w = w/10;
            }

        }
        return list;
    }
    
    public char choose(int n){
        char result = 'A';
        //I-1，V-5，X-10，L-50，C-100，D-500，M-1000
        switch(n){
            case 1000:
                result = 'M';
                break;
            case 500:
                result = 'D';
                break;
            case 100:
                result = 'C';
                break;
            case 50:
                result = 'L';
                break;
            case 10:
                result = 'X';
                break;
            case 5:
                result = 'V';
                break;
            case 1:
                result = 'I';
                break;
        }
        return result;
    }
}