• hdu2732


    题解:

    和上一题差不多

    然后注意格式

    代码:

    #include<cstdio>
    #include<cmath>
    #include<algorithm>
    #include<cstring>
    const int N=25;
    using namespace std;
    struct data{int to,ne,v;}e[500001];
    int r,c,d,T,cnt,ans,cas,mp[N][N],mark[N][N],q[802],h[802],fi[802];
    void ins(int u,int v,int w)
    {
        cnt++;e[cnt].to=v;
        e[cnt].ne=fi[u];
        fi[u]=cnt;
        e[cnt].v=w;
    }
    void insert(int u,int v,int w)
    {
        ins(u,v,w);
        ins(v,u,0);
    }
    int judge(int x1,int y1,int x2,int y2)
    {
        if (((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2))<=(d*d)&&mp[x1][y1]&&mp[x2][y2])
         return 1;
        return 0;
    }
    void build()
    {
        for (int x1=1;x1<=r;x1++)
         for (int y1=1;y1<=c;y1++)
          for (int x2=x1-d;x2<=x1+d;x2++)
           for (int y2=y1-d;y2<=y1+d;y2++)
        if (judge(x1,y1,x2,y2)&&(x1!=x2||y1!=y2))
         insert(mark[x1][y1]+400,mark[x2][y2],1e9); 
        for (int i=1;i<=r;i++)
         for (int j=1;j<=c;j++)
          if (mp[i][j])insert(mark[i][j],mark[i][j]+400,mp[i][j]);
    } 
    int bfs()
    {
        memset(h,-1,sizeof(h));
        int t=0,w=1,now;
        q[0]=h[0]=0;
        while (t<w)
         {
            now=q[t++];
            for (int i=fi[now];i;i=e[i].ne)
             if (e[i].v&&h[e[i].to]==-1)
              {
                h[e[i].to]=h[now]+1;
                q[w++]=e[i].to; 
              }
         }
        if (h[801]==-1)return 0;
        return 1;
    }
    int dfs(int x,int f)
    {
        if (x==801)return f;
        int used=0,w;
        for (int i=fi[x];i;i=e[i].ne)
         if (e[i].v&&h[e[i].to]==h[x]+1)
          {
            w=f-used;w=dfs(e[i].to,min(w,e[i].v));
            e[i].v-=w;e[i^1].v+=w;
            used+=w;
            if(used==f)return f;
          }
        if (!used)h[x]=-1;
        return used;
    }
    void doit()
    {
        scanf("%d%d",&r,&d);
        char ch[N];
        memset(mp,0,sizeof mp);
        memset(mark,0,sizeof mark);
        memset(fi,0,sizeof fi);
        memset(e,0,sizeof e);
        memset(q,0,sizeof q);
        memset(h,0,sizeof h); 
        cnt=1;
        ans=0;
        for (int i=1;i<=r;i++)
         {
               scanf("%s",ch);
               c=strlen(ch);
               for (int j=1;j<=c;j++)mp[i][j]=ch[j-1]-'0';
         }
        int tot=0; 
        for (int i=1;i<=r;i++)
         for (int j=1;j<=c;j++)
          {
              tot++;
            mark[i][j]=tot;
           }  
        for (int i=1;i<=r;i++)
         {
               scanf("%s",ch);
               for (int j=1;j<=c;j++)
             if (ch[j-1]=='L'){insert(0,mark[i][j],1);ans++;}
         }
        for (int i=1;i<=d;i++)
         for (int j=d+1;j<=r-d;j++)
          {
            insert(mark[j][i]+400,801,1e9);
            insert(mark[j][c-i+1]+400,801,1e9);
          }
        for (int i=1;i<=d;i++)
         for (int j=1;j<=c;j++)
          {
            insert(mark[i][j]+400,801,1e9);
            insert(mark[r-i+1][j]+400,801,1e9);
          }
        build();
        while (bfs())ans-=dfs(0,1e9);
        printf("Case #%d: ",++cas);
        if (ans==0)printf("no ");else printf("%d ",ans);
         if (ans<2)puts("lizard was left behind.");
        else puts("lizards were left behind.");  
    }
    int main()
    {
        scanf("%d",&T);
        while (T--)doit();
    }
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  • 原文地址:https://www.cnblogs.com/xuanyiming/p/8337040.html
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