Given an array of strings products
and a string searchWord
. We want to design a system that suggests at most three product names from products
after each character of searchWord
is typed. Suggested products should have common prefix with the searchWord. If there are more than three products with a common prefix return the three lexicographically minimums products.
Return list of lists of the suggested products
after each character of searchWord
is typed.
Example 1:
Input: products = ["mobile","mouse","moneypot","monitor","mousepad"], searchWord = "mouse" Output: [ ["mobile","moneypot","monitor"], ["mobile","moneypot","monitor"], ["mouse","mousepad"], ["mouse","mousepad"], ["mouse","mousepad"] ] Explanation: products sorted lexicographically = ["mobile","moneypot","monitor","mouse","mousepad"] After typing m and mo all products match and we show user ["mobile","moneypot","monitor"] After typing mou, mous and mouse the system suggests ["mouse","mousepad"]
Example 2:
Input: products = ["havana"], searchWord = "havana" Output: [["havana"],["havana"],["havana"],["havana"],["havana"],["havana"]]
Example 3:
Input: products = ["bags","baggage","banner","box","cloths"], searchWord = "bags" Output: [["baggage","bags","banner"],["baggage","bags","banner"],["baggage","bags"],["bags"]]
Example 4:
Input: products = ["havana"], searchWord = "tatiana" Output: [[],[],[],[],[],[],[]]
Constraints:
1 <= products.length <= 1000
- There are no repeated elements in
products
. 1 <= Σ products[i].length <= 2 * 10^4
- All characters of
products[i]
are lower-case English letters. 1 <= searchWord.length <= 1000
- All characters of
searchWord
are lower-case English letters.
class Trie { Trie[] children = new Trie[26]; List<String> suggesions = new ArrayList<>(); } class Solution { public List<List<String>> suggestedProducts(String[] products, String searchWord) { Arrays.sort(products); Trie root = new Trie(); // build tree for (String product : products) { Trie curTrie = root; char[] curArr = product.toCharArray(); for (char c : curArr) { if (curTrie.children[c - 'a'] == null) { curTrie.children[c - 'a'] = new Trie(); } curTrie = curTrie.children[c - 'a']; if (curTrie.suggesions.size() < 3) { curTrie.suggesions.add(product); } } } List<List<String>> res = new ArrayList<>(); char[] charArr = searchWord.toCharArray(); for (char c : charArr) { if (root != null) { root = root.children[c - 'a']; } res.add(root == null ? new ArrayList<>() : root.suggesions); } return res; } }