成绩转换
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 57281 Accepted Submission(s): 24928
Problem Description
输入一个百分制的成绩t，将其转换成对应的等级，具体转换规则如下：
90~100为A;
80~89为B;
70~79为C;
60~69为D;
0~59为E;
Input
输入数据有多组，每组占一行，由一个整数组成。
Output
对于每组输入数据，输出一行。如果输入数据不在0~100范围内，请输出一行：“Score is error!”。
Sample Input
56
67
100
123
Sample Output
E
D
A
Score is error!
#include <stdio.h>
int main()
{int n;
while(scanf("%d",&n)!=EOF)
{if(90<=n&&n<=100) printf("A
");
if(80<=n&&n<=89) printf("B
");
if(70<=n&&n<=79) printf("C
");
if(60<=n&&n<=69) printf("D
");
if(0<=n&&n<=59) printf("E
");
if(n<0||n>100) printf("Score is error!
");
}
return 0;
}
#include <stdio.h>
int main()
{int n;
while(scanf("%d",&n)!=EOF)
{
if(90<=n&&n<=100) printf("A
");
else if(80<=n&&n<=89) printf("B
");
else if(70<=n&&n<=79) printf("C
");
else if(60<=n&&n<=69) printf("D
");
else if(0<=n&&n<=59) printf("E
");
else printf("Score is error!
");
}
return 0;
}