Coder-Strike 2014

主要就是先将梯子移动到最左边或者最右边

k>n/2时移动到最右边

k<=n/2时移动到最左边

然后遍历一遍

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main(){
    int n,k;
    cin >> n >> k;
    string poster ;
    cin >> poster;
    if(k > n/2){
        for(int i = k-1 ; i < n-1; ++ i){
            cout<<"RIGHT"<<endl;
        }
        for(int i = n-1; i > 0; --i){
            cout<<"PRINT "<<poster[i]<<endl;
            cout<<"LEFT"<<endl;
        }
        cout<<"PRINT "<<poster[0]<<endl;
    }else{
        for(int i = k-1; i>0; --i) cout<<"LEFT"<<endl;
        for(int i = 0; i < n-1; ++i){
            cout<<"PRINT "<<poster[i]<<endl;
            cout<<"RIGHT"<<endl;
        }
        cout<<"PRINT "<<poster[n-1]<<endl;
    }
}