1001. Reverse Root

1001. Reverse Root

Time Limit: 2.0 second
Memory Limit: 64 MB

The problem is so easy, that the authors were lazy to write a statement for it!

Input

The input stream contains a set of integer numbers A_i (0 ≤ A_i ≤ 10¹⁸). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number A_i from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0 876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

#include <iostream>
#include <cstdio>
#include <cmath>
#include <vector>
using namespace std;

int main(){

    double n;
    vector <double> ans;
    while(cin >> n) ans.push_back(sqrt(n));
    for(int i = ans.size()-1; i>= 0 ; i--)
        printf("%.4f\n",ans[i]);
    return 0;
}