Python 忽略warning警告错误 + 跳过报错继续执行程序

 

如何主动产生warning错误：

import warnings

def fxn():

    warnings.warn("deprecated", DeprecationWarning)

with warnings.catch_warnings():

    warnings.simplefilter("ignore")

    fxn()

 

那么如何来控制警告错误的输出呢？

import warnings

warnings.filterwarnings("ignore")

 

如何忽略命令行下警告错误的输出呢？
python -W ignore yourscript.py

那么如何忽略全部的异常呢？下面是一个事例

import pandas as pd

dates=range(20161010,20161114)
pieces=[]
for date in dates:
try:
data=pd.read_csv('A_stock/overview-push-%d/stock overview.csv' %date, encoding='gbk')
pieces.append(data)
except Exception as e:
pass
continue
data=pd.concat(pieces)

参考：

https://www.cnblogs.com/blueel/p/3529517.html

https://blog.csdn.net/weixin_43307577/article/details/87710251