• PHP截取字符串


    1. 截取GB2312中文字符串

    <?php
    < ?php 
    //截取中文字符串
    function mysubstr($str, $start, $len) {
        $tmpstr = "";
        $strlen = $start + $len;
        for($i = 0; $i < $strlen; $i++) {
            if(ord(substr($str, $i, 1)) > 0xa0) {
                $tmpstr .= substr($str, $i, 2);
                $i++;
            } else
                $tmpstr .= substr($str, $i, 1);
        }
        return $tmpstr;
    }
    ?>

    2. 截取utf8编码的多字节字符串

    <?php
    < ?php
    //截取utf8字符串
    function utf8Substr($str, $from, $len)
    {
        return preg_replace('#^(?:[\x00-\x7F]|[\xC0-\xFF][\x80-\xBF]+){0,'.$from.'}'.
                           '((?:[\x00-\x7F]|[\xC0-\xFF][\x80-\xBF]+){0,'.$len.'}).*#s',
                           '$1',$str);
    }
    ?>
    3. UTF-8、GB2312都支持的汉字截取函数

    <?php
    < ?php
    /* 
    Utf-8、gb2312都支持的汉字截取函数 
    cut_str(字符串, 截取长度, 开始长度, 编码); 
    编码默认为 utf-8 
    开始长度默认为 0 
    */ 
     
    function cut_str($string, $sublen, $start = 0, $code = 'UTF-8') 

        if($code == 'UTF-8') 
        { 
            $pa = "/[\x01-\x7f]|[\xc2-\xdf][\x80-\xbf]|\xe0[\xa0-\xbf][\x80-\xbf]|[\xe1-\xef][\x80-\xbf][\x80-\xbf]|\xf0[\x90-\xbf][\x80-\xbf][\x80-\xbf]|[\xf1-\xf7][\x80-\xbf][\x80-\xbf][\x80-\xbf]/"; 
            preg_match_all($pa, $string, $t_string); 
     
            if(count($t_string[0]) - $start > $sublen) return join('', array_slice($t_string[0], $start, $sublen))."...";
            return join('', array_slice($t_string[0], $start, $sublen)); 
        } 
        else 
        { 
            $start = $start*2; 
            $sublen = $sublen*2; 
            $strlen = strlen($string); 
            $tmpstr = ''; 
     
            for($i=0; $i< $strlen; $i++) 
            { 
                if($i>=$start && $i< ($start+$sublen)) 
                { 
                    if(ord(substr($string, $i, 1))>129) 
                    { 
                        $tmpstr.= substr($string, $i, 2); 
                    } 
                    else 
                    { 
                        $tmpstr.= substr($string, $i, 1); 
                    } 
                } 
                if(ord(substr($string, $i, 1))>129) $i++; 
            } 
            if(strlen($tmpstr)< $strlen ) $tmpstr.= "..."; 
            return $tmpstr; 
        } 

     
    $str = "abcd需要截取的字符串"; 
    echo cut_str($str, 8, 0, 'gb2312'); 
    ?>
    4. BugFree 的字符截取函数

    <?php
    < ?php 
    /** 
     * @package     BugFree 
     * @version     $Id: FunctionsMain.inc.php,v 1.32 2005/09/24 11:38:37 wwccss Exp $ 
     * 
     * 
     * Return part of a string(Enhance the function substr()) 
     * 
     * @author                  Chunsheng Wang <wwccss@263.net
     * @param string  $String  the string to cut. 
     * @param int     $Length  the length of returned string. 
     * @param booble  $Append  whether append "...": false|true 
     * @return string           the cutted string. 
     */ 
    function sysSubStr($String,$Length,$Append = false) 

        if (strlen($String) < = $Length ) 
        { 
            return $String; 
        } 
        else 
        { 
            $I = 0; 
            while ($I < $Length) 
            { 
                $StringTMP = substr($String,$I,1); 
                if ( ord($StringTMP) >=224 ) 
                { 
                    $StringTMP = substr($String,$I,3); 
                    $I = $I + 3; 
                } 
                elseif( ord($StringTMP) >=192 ) 
                { 
                    $StringTMP = substr($String,$I,2); 
                    $I = $I + 2; 
                } 
                else 
                { 
                    $I = $I + 1; 
                } 
                $StringLast[] = $StringTMP; 
            } 
            $StringLast = implode("",$StringLast); 
            if($Append) 
            { 
                $StringLast .= "..."; 
            } 
            return $StringLast; 
        } 

     
    $String = "CodeBit.cn -- 简单、精彩、通用"; 
    $Length = "18"; 
    $Append = false; 
    echo sysSubStr($String,$Length,$Append); 
    ?>

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  • 原文地址:https://www.cnblogs.com/xingmeng/p/2887048.html
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