139. Word Break
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words.
Note:
- The same word in the dictionary may be reused multiple times in the segmentation.
- You may assume the dictionary does not contain duplicate words.
Example 1:
Input: s = "leetcode", wordDict = ["leet", "code"] Output: true Explanation: Return true because"leetcode"
can be segmented as"leet code"
.
Example 2:
Input: s = "applepenapple", wordDict = ["apple", "pen"] Output: true Explanation: Return true because"
applepenapple"
can be segmented as"
apple pen apple"
. Note that you are allowed to reuse a dictionary word.
Example 3:
Input: s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"] Output: false
题意:能否在wordDict中抽出几个单词(可以重复抽取)拼凑成s
代码如下:
/** * @param {string} s * @param {string[]} wordDict * @return {boolean} */ var wordBreak = function(s, wordDict) { var tmp=[]; for(var i=0;i<s.length+1;i++){ if(i===0) tmp[i]=true; else tmp[i]=false; } for(var i=1;i<=s.length;i++){ for(var j=0;j<i;j++){ if(tmp[j] && wordDict.includes(s.substring(j,i))){ tmp[i]=true; break; } } } return tmp[s.length]; };