找规律的题目an=an-1+(i+i%2)/2*2;
#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<iomanip>
#include<cmath>
#include<string>
using namespace std;
int main()
{
int i,j,ans[51];
ans[1]=1;
for(i=2;i<=50;i++)
{
ans[i]=ans[i-1]+(i+i%2)/2*2;
}
int n,t;
cin>>t;
while(t--)
{
cin>>n;
cout<<ans[n]<<endl;
}
return 0;
}