python:代码复用与函数递归

#recursion.py：打印斐波那契数列
def fact(n):
    if n==1 or n==2:
        return 1
    else:
        return fact(n-1)+fact(n-2)
while 1==1:
    test=eval(input("请输入数字："))
    for i in range(1,test+1):
        print("第{}次打印：".format(i),fact(i))