• 766. Toeplitz Matrix Toeplitz矩阵


    A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

    Now given an M x N matrix, return True if and only if the matrix is Toeplitz.

    Example 1:

    Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]]
    Output: True
    Explanation:
    1234
    5123
    9512
    
    In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.
    

    Example 2:

    Input: matrix = [[1,2],[2,2]]
    Output: False
    Explanation:
    The diagonal "[1, 2]" has different elements.
    

    Note:

    1. matrix will be a 2D array of integers.
    2. matrix will have a number of rows and columns in range [1, 20].
    3. matrix[i][j] will be integers in range [0, 99].


    1. class Solution:
    2. def isToeplitzMatrix(self, matrix):
    3. """
    4. :type matrix: List[List[int]]
    5. :rtype: bool
    6. """
    7. if not matrix or not matrix[0]:
    8. return False
    9. rowNum = max(0, len(matrix) - 1)
    10. colNum = max(0, len(matrix[0]) - 1)
    11. if rowNum is 0 or colNum is 0:
    12. return True
    13. for i in range(rowNum):
    14. for j in range(colNum):
    15. if matrix[i][j] != matrix[i + 1][j + 1]:
    16. return False
    17. return True
    18. # matrix = [
    19. # [1, 2, 3, 4],
    20. # [5, 1, 2, 3],
    21. # [9, 5, 1, 2]
    22. # ]
    23. # matrix = [
    24. # [1, 2],
    25. # [2, 2]
    26. # ]
    27. matrix = [
    28. [39, 24],
    29. [24, 39],
    30. [65, 24]
    31. ]
    32. #matrix = [[10], [11], [12]]
    33. s = Solution()
    34. res = s.isToeplitzMatrix(matrix)
    35. print(res)





  • 相关阅读:
    利用阻止冒泡解决点击页面除去本身触发事件
    vijos p1304 回文数
    vijos p1484 ISBN号码
    vijos p1449 字符串还原
    vijos p1217 乒乓球
    vijos P1911 珠心算测验
    vijos p1001 谁拿了最多奖学金
    vijos P1848 记数问题
    Catalan公式
    【HDOJ】2104 hide handkerchief
  • 原文地址:https://www.cnblogs.com/xiejunzhao/p/8331680.html
Copyright © 2020-2023  润新知