• 关于json解析中 解析多重json对象


    JSONObject rst = {"AIS-RST":"AIS-00000001","AIS-STATUS":"AIS-000000","RECORD":[{"0|5a4ed8721b71eeb4011b78184c6708bd":{"ANUM":"74","ATOTAL":"6","ISCHECKNUM":"69","ISNUM":"0","NOCHECKNUM":"0","NONUM":"0"}},{"0|5a4ed8721b71eeb4011b78186a2108be":{"ANUM":"29303","ATOTAL":"464","ISCHECKNUM":"29113","ISNUM":"19","NOCHECKNUM":"19","NONUM":"0"}}]};

      //解析rst,然后得到一个数组,再通过JSONArray数组解析出来

     JSONArray jsonDwa = (JSONArray) JSONArray.parseObject(rst).get("RECORD");

          //建造一个map用于后面将json对象解析出来后的key和value进行储存
    Map<String,String> mapMe = new HashMap<String, String>();

    Set set;
    int length = jsonDwa.size();
            //将数组进行遍历获得其内的json对象
    for (int i = 0; i <length ; i++) {
              //因为获得的是json对,所以用JSONObject来接收
    JSONObject jsonObject2 = (JSONObject) jsonDwa.get(i);
               //打印发现是json对象里面含有json对象
    System.out.println("YYYYYYYYYY"+jsonObject2);
              //用一个set将json对象进行迭代,然后将其key和value分别放进map,这样就获得了json的key和value
    set = jsonObject2.keySet();
    for(Object key : set){
    String dwaSet = (String) key;
    mapMe.put(dwaSet,jsonObject2.get(dwaSet).toString());
    }
    }
    System.out.println("mapMe"+ JSON.toJSONString(mapMe)+mapMe.size());

    }catch (Exception e){
    e.printStackTrace();
    }
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  • 原文地址:https://www.cnblogs.com/xiaoxiao0314/p/6095563.html
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