• Lc21_合并两个有序链表


    //将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。 
    //
    // 
    //
    // 示例: 
    //
    // 输入:1->2->4, 1->3->4
    //输出:1->1->2->3->4->4
    // 
    // Related Topics 链表
    
    package leetcode.editor.cn;
    
    import com.example.demo.ArrayConvertLinkedList;
    import com.example.demo.ListNode;
    
    //Java:合并两个有序链表
    public class P21MergeTwoSortedLists{
        public static void main(String[] args) {
            Solution solution = new P21MergeTwoSortedLists().new Solution();
            // TO TEST
            int[] array = {1,2,4};
            int[] array1 = {1,3,4};
            ListNode head = ArrayConvertLinkedList.arrayToNode(array);
            ListNode head1 = ArrayConvertLinkedList.arrayToNode(array1);
            ListNode res = solution.mergeTwoLists(head,head1);
            ArrayConvertLinkedList.printNode(res);
        }
        //leetcode submit region begin(Prohibit modification and deletion)
    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode() {}
     *     ListNode(int val) { this.val = val; }
     *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
     * }
     */
    class Solution {
        public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
           if(l1==null){
               return l2;
           }else if(l2==null){
               return l1;
           }else if(l1.val<=l2.val){
               l1.next = mergeTwoLists(l1.next,l2);
               return l1;
           }else{
               l2.next = mergeTwoLists(l1,l2.next);
               return l2;
           }
        }
    }
    //leetcode submit region end(Prohibit modification and deletion)
    
    }
    
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  • 原文地址:https://www.cnblogs.com/xiaoshahai/p/13267971.html
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