206. 反转链表
反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL
输出: 5->4->3->2->1->NULL
进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
Stack<Integer> stack = new Stack<Integer>();
while (head != null) {
stack.push(head.val);
head = head.next;
}
ListNode dummy = new ListNode(0);
ListNode temp = dummy;
while (!stack.isEmpty()) {
temp.next = new ListNode(stack.pop());
temp = temp.next;
}
return dummy.next;
}
}