import java.util.Stack; /* * Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. Open brackets must be closed in the correct order. Note that an empty string is also considered valid. Example 1: Input: "()" Output: true Example 2: Input: "()[]{}" Output: true Example 3: Input: "(]" Output: false Example 4: Input: "([)]" Output: false Example 5: Input: "{[]}" Output: true 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/valid-parentheses 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 */ public class Lc20 { public static boolean isValid(String s) { Stack<Character> stack = new Stack<Character>(); boolean isValid = false; char[] ch = s.toCharArray(); for (char c : ch) { if ('(' == c) { stack.push(c); } else if ('[' == c) { stack.push(c); } else if ('{' == c) { stack.push(c); } else if (!stack.isEmpty()) { if (')' == c) { Character temp = stack.pop(); if ('(' != temp) { return false; } } else if (']' == c) { Character temp = stack.pop(); if ('[' != temp) { return false; } } else if ('}' == c) { Character temp = stack.pop(); if ('{' != temp) { return false; } } } else { return false; } } if (stack.isEmpty()) { isValid = true; } return isValid; } public static void main(String[] args) { String s = "{"; System.out.println(isValid(s)); } }