问题描述:
Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1 / / 2 3 2 3 [1,2,3], [1,2,3] Output: true
Example 2:
Input: 1 1 / 2 2 [1,2], [1,null,2] Output: false
Example 3:
Input: 1 1 / / 2 1 1 2 [1,2,1], [1,1,2] Output: false
思路:
考虑递归解法,将大问题化解为无数个类似的小问题
# Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def isSameTree(self, p: TreeNode, q: TreeNode) -> bool: if p == None and q ==None: return True elif p == None or q ==None or p.val != q.val: return False if p.val == q.val : return self.isSameTree(p.left,q.left) and self.isSameTree(p.right,q.right)