• oracle——笔记——简单查询语句


    create table emp2 ( empno number(4),
                        ename varchar2(10),
                        job varchar2(9),
                        mgr number(4),
                        hiredate date,
                        sal number(7,2),
                        comm number(7,2),
                        deptno number(2) 
                     );
    -----------------------------------------------------------------------------------------------------------
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7369, 'SMITH', 'CLERK', 7902, to_date('17-12-1980', 'dd-mm-yyyy'), 800.00, null, 20);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7499, 'ALLEN', 'SALESMAN', 7698, to_date('20-02-1981', 'dd-mm-yyyy'), 1600.00, 300.00, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7521, 'WARD', 'SALESMAN', 7698, to_date('22-02-1981', 'dd-mm-yyyy'), 1250.00, 500.00, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7566, 'JONES', 'MANAGER', 7839, to_date('02-04-1981', 'dd-mm-yyyy'), 2975.00, null, 20);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7654, 'MARTIN', 'SALESMAN', 7698, to_date('28-09-1981', 'dd-mm-yyyy'), 1250.00, 1400.00, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7698, 'BLAKE', 'MANAGER', 7839, to_date('01-05-1981', 'dd-mm-yyyy'), 2850.00, null, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7782, 'CLARK', 'MANAGER', 7839, to_date('09-06-1981', 'dd-mm-yyyy'), 2450.00, null, 10);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7788, 'SCOTT', 'ANALYST', 7566, to_date('19-04-1987', 'dd-mm-yyyy'), 3000.00, null, 20);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7839, 'KING', 'PRESIDENT', null, to_date('17-11-1981', 'dd-mm-yyyy'), 5000.00, null, 10);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7844, 'TURNER', 'SALESMAN', 7698, to_date('08-09-1981', 'dd-mm-yyyy'), 1500.00, 0.00, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7876, 'ADAMS', 'CLERK', 7788, to_date('23-05-1987', 'dd-mm-yyyy'), 1100.00, null, 20);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7900, 'JAMES', 'CLERK', 7698, to_date('03-12-1981', 'dd-mm-yyyy'), 950.00, null, 30);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7902, 'FORD', 'ANALYST', 7566, to_date('03-12-1981', 'dd-mm-yyyy'), 3000.00, null, 20);
    
    insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
    values (7934, 'MILLER', 'CLERK', 7782, to_date('23-01-1982', 'dd-mm-yyyy'), 1300.00, null, 10);
    
    =============================================================================================================================
    
    create table dept2 ( deptno number(2),
                         dname varchar2(14),
                         loc varchar2(13)
                       );
    
    ----------------------------------------------------
    
    insert into dept2 (DEPTNO, DNAME, LOC)
    values (10, 'ACCOUNTING', 'NEW YORK');
    
    insert into dept2 (DEPTNO, DNAME, LOC)
    values (20, 'RESEARCH', 'DALLAS');
    
    insert into dept2 (DEPTNO, DNAME, LOC)
    values (30, 'SALES', 'CHICAGO');
    
    insert into dept2 (DEPTNO, DNAME, LOC)
    values (40, 'OPERATIONS', 'BOSTON');
    
    ============================================================
    
    create table salgrade2 ( grade number,
                             losal number,
                             hisal number
                           );
    
    --------------------------------------------------
    
    insert into salgrade2 (GRADE, LOSAL, HISAL)
    values (1, 700, 1200);
    
    insert into salgrade2 (GRADE, LOSAL, HISAL)
    values (2, 1201, 1400);
    
    insert into salgrade2 (GRADE, LOSAL, HISAL)
    values (3, 1401, 2000);
    
    insert into salgrade2 (GRADE, LOSAL, HISAL)
    values (4, 2001, 3000);
    
    insert into salgrade2 (GRADE, LOSAL, HISAL)
    values (5, 3001, 9999);
    
    
    ========================================================
    
    select * from emp2;
    
    select * from dept2;
    
    select * from salgrade2;
    
    =====================================
    select * from emp2;        --employee2 员工表
    select * from dept2;       --department2 部门表
    select * from salgrade2;   -- salary grade2 工资等级表
    
    -----------------------------------------------------
    emp2
    
    empno    员工编号
    ename    员工姓名
    job      工作/工种
    mgr      manager上级编号
    hiredate 入职日期
    sal      salary 工资
    comm     奖金/津贴
    deptno   部门编号
    ---------------------
    
    dept2
    
    deptno  部门号
    dname   部门名称
    loc     所在地
    ---------------------------
    salgrade2
    
    grade                   等级
    losal lowest salary     最低工资
    hisal high salary       最高工资
    
    =============================================
    

    数据查询语句:
    select from where





    查询emp2表中,所有员工的姓名、工资、部门号:
    select ename,sal,deptno from emp2;




    查询emp2表中,工资大于1500 的员工信息:
    select * from emp2 where sal > 1500;





    查询emp2表中,上级是7698 的员工姓名和津贴:
    select ename,comm from emp2 where mgr = 7698;





    列的别名:
    select ename,sal,deptno from emp2; select ename 姓名,sal 工资,deptno 部门号 from emp2; select ename as 姓名,sal as 工资,deptno as 部门号 from emp2; select ename as e,sal as s,deptno as d from emp2; select ename as "Esc",sal as "alS",deptno as "dDD" from emp2; select ename as "e%",sal as "s#",deptno as "d()" from emp2;



    ==============================================================================================================

    算术运算
    + - * / () 支持数值型和日期型(只能加减)数据:




    查询每个员工的年薪:
    select ename,sal,sal*12 from emp2;




    给20部门员工,涨薪300之后,工资是多少?:
    select ename,sal,sal+300 from emp2 where deptno = 20;





    查询每名员工的 工资奖金和 :
    select sal,comm,sal+comm from emp2;





    运算中如果有空值,那么最后结果为空
    --空值替换 nvl() select sal,comm,nvl(comm,0),sal+nvl(comm,0) from emp2; select * from emp2; insert into emp2(empno) values(1122); delete from emp2 where empno = 1122; select ename,nvl(ename,'未知') from emp2;







    连接符 :
    select ename,sal from emp2; select ename||'的工资是'||sal||',部门是'||deptno from emp2;





    去重


    查询emp中,有多少个部门:
    select distinct deptno from emp2;




    查询emp中,有多少种工作
    select distinct job from emp2;







    where 比较运算符 一般的比较运算符 > >= <= < = != <> 特殊的比较运算符 between……and…… in(……) like …… 像 模糊查询 is null 空值




    select * from emp2 where comm is null;


    select * from emp2 where comm is not null;







    查询工资在1500 到
    3000 的员工信息: select * from emp2 where sal between 1500 and 3000; --闭区间 下限 上限
    select * from emp2 where sal >= 1500 and sal <= 3000;




    查询从事CLERK或SALESMAN 的员工信息:
    1)字符串 2)关于大小写 select * from emp2 where job in('CLERK','SALESMAN'); select * from emp2 where job = 'CLERK' or job = 'SALESMAN' ; select * from emp2 where sal in(1500,3000); select * from emp2 where sal = 1500 or sal = 3000;







    like select * from emp2 where ename like 'S%';





    % sql里的% 等同于linux的* ,代表零个或多个任意字符 _ 代表一个任意字符 select * from emp2 where ename like 'S_ITH'; select t.*,t.rowid from emp2 t; select emp2.*,rowid from emp2;


    查询以S
    %开头的员工信息: select * from emp2 where ename like 'S\%%' escape '\'; escape '\':定义\这个符号后面符号位普通字符串,不是系统里默认的符号。即转义 select * from emp2 where ename like 'S|%%' escape '|'; select * from emp2 where ename like 'S%\%' escape '\';

    escape: 用来转译的,比如数据库中有个表 test字段name 中存了字符'%',那么我查询的时候如果想查询第二位是 '%'的记录就要用到模糊查询,

    但是
    '%'是模糊查询的通配符,我不能如下查询: select * from test where name like '_%%';


    这样系统不会把第二个【
    %】当做字符,只能转译,转译默认的符号是 【\】 select * from test where name like '_\%%';


    但是可以自定义转义符,这时候就用
    escape,比如定义【*】为转义符 select * from test where name like '_*%%' escape '*';




    -----------------------------------------------------------------------------------------------------





    逻辑运算符 and or not () 运算优先级:not > and > or ,()优先级最高


    查询,
    20 部门中,从事CLERK 工作的员工: select * from emp2 where deptno = 20 and job = 'CLERK';


    查询,
    30 部门中,奖金为空的员工信息: select * from emp2 where deptno = 30 and comm is null;


    查询,除10 部门之外,工资大于1500 的员工信息:
    select * from emp2 where deptno != 10 and sal > 1500;


    查询,工作是SALESMAN ,或工资不小于3000 的员工:
    select * from emp2 where job = 'SALESMAN' or sal >= 3000;

    查询,工作不是SALESMAN ,也不是CLERK 的员工:
    select * from emp2 where job != 'SALESMAN' and job != 'CLERK'; select * from emp2 where job in('SALESMAN','CLERK'); select * from emp2 where job not in('SALESMAN','CLERK');


    查询,工作是SALESMAN,或,工作是PRESIDENT并且工资大于1500的员工信息:
    select * from emp2 where job = 'SALESMAN' or job = 'PRESIDENT' and sal > 1500;



    查询,工作是SALESMAN或PRESIDNET,并且工资大于1500 的员工信息:
    select * from emp2 where (job = 'SALESMAN' or job = 'PRESIDENT') and sal > 1500; select * from emp2 where job in('SALESMAN','PRESIDENT') and sal > 1500;








    order by 排序 select from where order by 列名|别名|算术表达式|函数 order by 列1,别名,函数 order by 列1,列2 desc; order by的位置:在整个查询语句的最后多次排序





    select * from emp2 order by sal; --升序 select * from emp2 order by sal asc; --升序 select * from emp2 order by sal desc; --降序 select ename 姓名,job 工作 from emp2 where deptno = 20 order by 姓名 desc;



    查询员工信息,结果按照工资奖金和 升序排序:
    select emp2.*,sal+nvl(comm,0) from emp2 order by sal+nvl(comm,0);


    查询员工信息,结果按照部门号排序;如果部门号相同,按照工资降序排序
    select * from emp2 order by deptno asc,sal desc;



    函数 单组函数 一个值对应一个结果 分组函数
    /聚合函数 多个值对应一个结果 avg() sum() 单组函数 --字符函数 UPPER() LOWER() INITCAP() ---字母大小写 大写 小写 首字母大写 replace() substr() concat() nvl() nvl2() 替换 截取 连接


    select ename,lower(ename),initcap(ename) from emp2; select t.*,t.rowid from emp2 t; select * from emp2 where lower(job) = 'clerk'; select ename,replace(ename,'S','s') from emp2; select ename,substr(ename,2,3) from emp2; 起始位,长度


    查询工作名称以SALES 开头的员工信息:
    select * from emp2 where job like 'SALES%'; select * from emp2 where substr(job,1,5) = 'SALES'; select ename||'的工资是'||sal||deptno from emp2; select concat(ename,sal) from emp2; select concat(concat(ename,'的工资是'),sal) from emp2;





    函数是可以嵌套的
    select substr(concat(ename,'的工资是'),5,5) from emp2; select comm,nvl(comm,0),nvl2(comm,1000,0) from emp2; 非空替换,空值替换






    数值函数
    round(x[,y]) 取整或保留指定小数位,规则:四舍五入 trunc(x[,y]) 取整或保留指定小数位,规则:截断 mod(x,y) 取模/取余 round(5.72) = 6 round(5.718,2) = 5.72 round(04.718,-1) = 0 trunc(5.72) = 5 trunc(5.718,2) = 5.71 trunc(05.718,-1) = 0 select round(5.72), round(5.718,2),round(5.718,-1) from dual; select trunc(5.718,2),mod(8,4),mod(10,3) from dual;

    dual表 作用:语句补全
    select * from dual; select sysdate from dual; select 12*15,round(1000/23,2) from dual; select Sys_Context('userenv','db_name') from dual;--查看当前数据库 名 select Dbms_Random.random from dual;--获得一个随机数 select Dbms_Random.value(10,20) from dual;--获得一个随机数











    日期函数 使用insert,新增一条记录: 员工编号:
    1122 员工工作:SALESMAN 入职日期:2018年7月1号 insert into 表名(列名) values(列对应的值); insert into emp(empno,job,hiredate) values(1122,'SALESMAN','01-7月-18'); insert into emp(empno,job,hiredate) values(1122,'SALESMAN','2018-7-1'); select * from emp; --1)默认日期格式 select * from nls_session_parameters; alter session set NLS_DATE_FORMAT='YYYY-MM-DD'; alter session set NLS_DATE_FORMAT='DD-MON-RR'; --2) 日期函数 to_date(日期,格式) insert into emp(empno,job,hiredate) values(1123,'SALESMAN',to_date('10-1-2018','MM-DD-YYYY')); --查询入职日期早于1981年9 月30 号的员工信息 select from where hiredate < to_date()
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  • 原文地址:https://www.cnblogs.com/xiaobaibailongma/p/12258070.html
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