• leetcode 190. Reverse Bits (int)数字旋转 ---------- java


    Reverse bits of a given 32 bits unsigned integer.

    For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

    要求将一个无符号数进行二进制旋转,简单的位操作即可。。

    public class Solution {
        // you need treat n as an unsigned value
        public int reverseBits(int n) {
            int result = 0;
            for (int i = 0; i < 32; i++){
                result = result | (((n >> i & 1) << (31 - i)));
            }
            return result;
        }
    }

    也可以优化一下。

    public int reverseBits(int n) {
        if (n == 0) return 0;
        
        int result = 0;
        for (int i = 0; i < 32; i++) {
            result <<= 1;
            if ((n & 1) == 1) result++;
            n >>= 1;
        }
        return result;
    }
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  • 原文地址:https://www.cnblogs.com/xiaoba1203/p/6610444.html
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