• hdu5475(线段树单点修改,统计区间乘积)


    题目意思:

    给定a*b*c*d*e*f*....,可以在某一步去掉前面的一个因子,每次回答乘积。

    #include <cstdio>
    #include <cstring>
    #include <cstdlib>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    #include <cmath>
    #define LL long long
    using namespace std;
    LL Q,MOD;
    //线段树
    //区间每点增值,求区间和
    const int maxN = 110000;
    struct node
    {
        int lt, rt;
        LL val;
    }tree[4*maxN];
    
    //向上更新
    void pushUp(int id)
    {
        tree[id].val = (tree[id<<1].val * tree[id<<1|1].val)%MOD;
    }
    
    //建立线段树
    void build(int lt, int rt, int id)
    {
        tree[id].lt = lt;
        tree[id].rt = rt;
        tree[id].val = 1;//每段的初值,根据题目要求
        if (lt == rt)
        {
            tree[id].val=1;
            return;
        }
        int mid = (lt+rt)>>1;
        build(lt, mid, id<<1);
        build(mid+1, rt, id<<1|1);
        pushUp(id);
    }
    
    //增加区间内每个点固定的值
    void add(int lt, int rt, int id, int pls)
    {
        if (lt <= tree[id].lt && rt >= tree[id].rt)
        {
            if(pls!=-1)
            {
              tree[id].val *= pls;
              tree[id].val %= MOD;
            }
            if(pls==-1)
              tree[id].val =1;
            return;
        }
        int mid = (tree[id].lt+tree[id].rt)>>1;
        if (lt <= mid)
            add(lt, rt, id<<1, pls);
        if (rt > mid)
            add(lt, rt, id<<1|1, pls);
        pushUp(id);
    }
    
    //查询某段区间内的和
    LL query(int lt, int rt, int id)
    {
        if (lt <= tree[id].lt && rt >= tree[id].rt)
            return tree[id].val;
        int mid = (tree[id].lt+tree[id].rt)>>1;
        LL ans = 1;
        if (lt <= mid)
            ans = (ans * query(lt, rt, id<<1) ) %MOD;
        if (rt > mid)
            ans = (ans * query(lt, rt, id<<1|1) ) %MOD;
        return ans;
    }
    
    int main()
    {
        //freopen("test.txt","r",stdin);
        int t;
        scanf("%d",&t);
        int Case=0;
        while(t--)
        {
            scanf("%I64d%I64d",&Q,&MOD);
            build(1,Q,1);
            printf("Case #%d:
    ",++Case);
            for(int i=1;i<=Q;i++)
            {
                LL x,m;
                scanf("%I64d%I64d",&x,&m);
                if(x==1)
                  add(i,i,1,m);
                else if(x==2)
                  add(m,m,1,-1);
                printf("%I64d
    ",tree[1].val);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/xianbin7/p/4867533.html
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