• JDBC-用户登录验证(sql注入)


    需求:实现用户登录功能

    描述:提供一个登陆的入口,可以让用户输入用户名和密码,提交信息后,java程序收集用户信息,
    java程序连接数据库,校验用户名和密码

    这种方式会有漏洞存在,导致sql注入;导致sql注入的根本原因是用户输入含有sql语句关键字,
    并且这些关键字参与了sql语句的编译过程,导致sql语句原意被扭曲,进而达到sql注入

    import java.util.HashMap;
    import java.util.Map;
    import java.util.Scanner;
    import java.sql.*;
    
    public class JdbcTest06 {
        public static void main(String[] args) {
            //1.初始化界面,创建Map集合接收用户名和密码
            Map<String,String> userInfo  = initUI();
            //2.通过loginSuccess的值判断登陆成功与否
            boolean loginSuccess = login(userInfo);
            System.out.println(loginSuccess ? "登陆成功":"登陆失败");
        }
    
        private static boolean login(Map<String, String> userInfo) {
            boolean loginSuccess = false;
            Connection con = null;
            Statement state = null;
            ResultSet rs = null;
            try {
                Class.forName("com.mysql.jdbc.Driver");
                con = DriverManager.getConnection("jdbc:mysql://127.0.0.1:3306/firstbase", "root", "123456");
                state = con.createStatement();
                String userName = userInfo.get("userName");
                String password = userInfo.get("password");
                // 这种方式会有漏洞存在,导致sql注入;导致sql注入的根本原因是用户输入含有sql语句关键字,
                // 并且这些关键字参与了sql语句的编译过程,导致sql语句原意被扭曲,进而达到sql注入
                String sql = "select * from t_users where username = '"+ userName +"' and password = '"+ password +"'";
                rs = state.executeQuery(sql);
                if (rs.next()){
                    loginSuccess = true;
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
            return loginSuccess;
        }
    
        private static Map<String,String> initUI() {
            Scanner sc = new Scanner(System.in);
            System.out.println("请输入用户名:");
            String userName = sc.nextLine();
            System.out.println("请输入密码:");
            String password = sc.nextLine();
            Map<String, String> userInfo = new HashMap<>();
            userInfo.put("userName", userName);
            userInfo.put("password", password);
            return userInfo;
        }
    }
    
    
    When nothing seems to help, I go look at a stonecutter hammering away at his rock, perhaps a hundred times without as much as a crack showing in it. Yet at the hundred and first blow it will split in two, and I know it was not that blow that did it, but all that had gone before. -- Jacob Riis
  • 相关阅读:
    oracle之修改/忘记用户密码
    linux 使用错误总结
    oracle数据库之用户管理
    linux命令使用总结
    linux各种压缩包的压缩和解压方法
    logback将日志写入不同文件夹里
    nginx下配置多个web服务
    OKHttp3学习
    linux 发送 post 请求
    maven 项目下 Maven Dependencies 下列表为空
  • 原文地址:https://www.cnblogs.com/xhwy-1234/p/13942047.html
Copyright © 2020-2023  润新知