• 查询表结构sql


     1 SELECT   CASE WHEN col.colorder = 1 THEN obj.name ELSE '' END AS 表名, col.colorder AS 序号, col.name AS 列名, 
     2                 ISNULL(ep.value, N'') AS 列说明, t.name AS 数据类型, col.length AS 长度, ISNULL(COLUMNPROPERTY(col.id, col.name, 
     3                 'Scale'), 0) AS 小数位数, CASE WHEN COLUMNPROPERTY(col.id, col.name, 'IsIdentity') 
     4                 = 1 THEN '' ELSE '' END AS 标识, CASE WHEN EXISTS
     5                     (SELECT   1
     6                      FROM      dbo.sysindexes si INNER JOIN
     7                                      dbo.sysindexkeys sik ON si.id = sik.id AND si.indid = sik.indid INNER JOIN
     8                                      dbo.syscolumns sc ON sc.id = sik.id AND sc.colid = sik.colid INNER JOIN
     9                                      dbo.sysobjects so ON so.name = si.name AND so.xtype = 'PK'
    10                      WHERE   sc.id = col.id AND sc.colid = col.colid) THEN '' ELSE '' END AS 主键, 
    11                 CASE WHEN col.isnullable = 1 THEN '' ELSE '' END AS 允许空, ISNULL(comm.text, N'') AS 默认值
    12 FROM      syscolumns AS col LEFT OUTER JOIN
    13                 systypes AS t ON col.xtype = t.xusertype INNER JOIN
    14                 sysobjects AS obj ON col.id = obj.id AND obj.xtype = 'U' AND obj.status >= 0 LEFT OUTER JOIN
    15                 syscomments AS comm ON col.cdefault = comm.id LEFT OUTER JOIN
    16                 sys.extended_properties AS ep ON col.id = ep.major_id AND col.colid = ep.minor_id AND 
    17                 ep.name = 'MS_Description' LEFT OUTER JOIN
    18                 sys.extended_properties AS epTwo ON obj.id = epTwo.major_id AND epTwo.minor_id = 0 AND 
    19                 epTwo.name = 'MS_Description'
    20 WHERE   (obj.name = 'TB_ROOM_STATE')
    21 ORDER BY 序号
  • 相关阅读:
    0531day05
    0530day04
    0529day03
    0528day02
    0527day01
    0527学习心得
    javascript 2
    javascript
    CSS
    CSS知识
  • 原文地址:https://www.cnblogs.com/xbq8080/p/6118183.html
Copyright © 2020-2023  润新知