• Python 根据MD5判断相同文件


    import hashlib
    import os
    import send2trash
    import time
    
    '''
    根据MD5,查找一个目录下的相同文件,并且可以选择是否删除(只是删除到回收站)
    '''
    
    def getMD5(path):
        f=open(path,'rb')
        d5 = hashlib.md5()      #生成一个hash的对象
        with open(path,'rb') as f:
            while True:
                content = f.read(40960)
                if not content:
                    break
                d5.update(content)   # 每次读取一部分,然后添加到hash对象里
        # print('MD5 : %s' % d5.hexdigest())
        return d5.hexdigest()        # 打印16进制的hash值
    
    def getSha512(path):
        f = open(path, 'rb')
        sh = hashlib.sha512()
        with open(path,'rb') as f:
            while True:
                content = f.read(40960)
                if not content:
                    break
                sh.update(content)
        # print(sh.hexdigest())
        return sh.hexdigest()
    
    # 装饰器,计算时间用的
    def timer(func):   # 高阶函数:以函数作为参数
        def deco(*args,**kwargs):    # 嵌套函数,在函数内部以 def 声明一个函数,接受 被装饰函数的所有参数
            time1 = time.time()
            func(*args,**kwargs)
            time2 = time.time()
            use_time = round(time2-time1,1)
            print('Elapsed %ss' %(use_time))
        return deco    # 注意,返回的函数没有加括号!所以返回的是一个内存地址,而不是函数的返回值
        
    @timer
    def walk(path):
        size = 0
        x = input('Want to delete duplicate file? y/n
    ')
        if x.lower() == 'y':
            delete = True
        else:
            delete = False
        dict = {}
        n = 1
        for folder,subfolder,filenames in os.walk(path):
            for filename in filenames:
                print('
    Has scanned %s files' %n,end='')
                root = os.path.join(folder,filename)
                md5 = getMD5(root)
                if md5 in dict.keys():
                    # sha1 = getSha512(root)
                    # sha2 = getSha512(dict[md5])
                    # if sha1 == sha2:
                    # 发送到回收站
                    if delete == True:
                        send2trash.send2trash(dict[md5])
                    print('
    %s
    %s
    ' %(root,dict[md5]))
                    # 获取文件大小
                    fsize = os.path.getsize(root)
                    size += fsize
                else:
                    pass
                dict[md5] = root
                n += 1
        # 处理文件大小的单位 M
        size = size/float(1024*1024)
        size = round(size,2)
        if delete == True:
            print('
    Saved %sM space.' % size)
        else:
            print("
    Wasted %sM sapce." %size)
    
    
    if __name__ =="__main__":
        x = input('Input path:')
        walk(x)
  • 相关阅读:
    SocketChannel 例子(转)
    多态(Polymorphism)的实现机制(上)--C++篇
    多态(Polymorphism)的实现机制(下)--Java篇
    java volatitle 多线程问题
    线程BlockingQueue (转)
    java 多态,和方法覆盖分析(转)
    MFC 调试技巧
    strlen与sizeof区别(转载)
    杭电1048
    杭电2013
  • 原文地址:https://www.cnblogs.com/wztshine/p/12363270.html
Copyright © 2020-2023  润新知