• zoj 1109 Language of FatMouse(字典树)


    Language of FatMouse

    Time Limit: 10 Seconds      Memory Limit: 32768 KB

    We all know that FatMouse doesn't speak English. But now he has to beprepared since our nation will join WTO soon. Thanks to Turing we havecomputers to help him.

    Input Specification

    Input consists of up to 100,005 dictionary entries, followed by a blankline, followed by a message of up to 100,005 words. Each dictionaryentry is a line containing an English word, followed by a space and a FatMouse word.No FatMouse word appears more than once in thedictionary. The message is a sequence of words in the language of FatMouse,one word on each line. Each word in the input is a sequence of at most 10lowercase letters.

    Output Specification

    Output is the message translated to English, one word per line. FatMouse words not in the dictionary should be translated as "eh".

    Sample Input

    dog ogday
    cat atcay
    pig igpay
    froot ootfray
    loops oopslay
    
    atcay
    ittenkay
    oopslay
    

    Output for Sample Input

    cat
    eh
    

    loops

    题解:建科字典树,单词插入的结尾记录该单词相应的单词的下标,查询就可以。

    #include<cstring>
    #include<algorithm>
    #include<cstdio>
    #include<iostream>
    #include<cstdlib>
    
    #define N 100020
    
    using namespace std;
    
    char s[12];
    char ans[N][12];
    
    struct Trie {
        int id;
        struct Trie *nxt[26];
        Trie() {
            id=0;
            for(int i=0; i<26; i++) {
                nxt[i]=NULL;
            }
        }
    };
    
    void Trie_Inser(Trie *p,char s[],int id) {
        int i=0;
        Trie *q=p;
        while(s[i]) {
            int nx=s[i]-'a';
            if(q->nxt[nx]==NULL) {
                q->nxt[nx]=new Trie;
            }
            i++;
            q=q->nxt[nx];
        }
        q->id=id;
    }
    
    int Trie_Serch(Trie *p,char s[]) {
        Trie *q=p;
        int i=0;
        while(s[i]) {
            int nx=s[i]-'a';
            if(q->nxt[nx]==NULL)return 0;
            q=q->nxt[nx];
            i++;
        }
        return q->id;
    }
    
    int main() {
        //freopen("test.in","r",stdin);
        Trie *p=new Trie;
        int id=1;
        char a[40];
        while(1) {
            gets(a);
            if(a[0]=='')break;
            int l=0;
            int len=strlen(a);
            int i;
            for(i=0; i<len; i++) {
                if(a[i]==' ')break;
                ans[id][l++]=a[i];
            }
            ans[id][l]='';
            l=0;
            i++;
            for(; i<len; i++) {
                s[l++]=a[i];
            }
            s[l]='';
            //printf("%s %s
    ",ans[id],s);
            Trie_Inser(p,s,id);
            id++;
        }
        while(~scanf("%s",s)) {
            id=Trie_Serch(p,s);
            if(id==0) {
                printf("eh
    ");
            } else {
                printf("%s
    ",ans[id]);
            }
        }
        return 0;
    }
    


  • 相关阅读:
    C语言丨二维数组常用的4种表示方法
    据说程序员最怕命名!这个 6300 Star 的手册能帮上忙
    C语言基础丨(六)程序结构——分支(选择)结构【2】
    系统管理员应该知道的 20 条 Linux 命令!越早学会越好!
    憋不住了!这8 个 MySQL 陷阱,我不得不说一下...
    记录一次@Around使用不正确造成的StackOverflowError
    【java基础】为何e1==(e1=e2)为false
    《Java程序性能优化》subString()方法的内存泄露
    【爬虫】花瓣采集下载器
    SpringMVC容器加载流程总结
  • 原文地址:https://www.cnblogs.com/wzjhoutai/p/6753194.html
Copyright © 2020-2023  润新知