Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:
2 / 1 3
Binary tree [2,1,3]
, return true.
Example 2:
1 / 2 3
Binary tree [1,2,3]
, return false.
题目含义:判断一个二叉树是否为二叉搜索树
思路:按照中序将树转换为数组,然后判断是否为递增
1 public void inorder(TreeNode root) { 2 if (root == null) return; 3 inorder(root.left); 4 values.add(root.val); 5 inorder(root.right); 6 } 7 8 public boolean isValidBST(TreeNode root) { 9 inorder(root); 10 for (int i = 0; i < values.size() - 1; i++) { 11 if (values.get(i) >= values.get(i + 1)) return false; 12 } 13 return true; 14 }