Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ]
public List<List<Integer>> threeSum(int[] nums) {
Arrays.sort(nums);
List<List<Integer>> res = new LinkedList<>();
for (int i = 0; i < nums.length; i++) {
if (i > 0 && nums[i] == nums[i - 1]) continue;
int low = i + 1, high = nums.length - 1;
while (low < high) {
if (nums[i] + nums[low] + nums[high] == 0) {
res.add(Arrays.asList(nums[i], nums[low], nums[high]));
while (low < high && nums[low] == nums[low + 1]) low++;
while (low < high && nums[high] == nums[high - 1]) high--;
low++;
high--;
} else if (nums[i] + nums[low] + nums[high] > 0) high--;
else low++;
}
}
return res;
}
类似题目:18. 4Sum