C#实现字符串去重

方法一 注：需要.net 3.5框架的支持

string s = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
s = string.Join(",", s.Split(',').Distinct().ToArray());

方法二

class Program
    {
        static void Main(string[] args)
        {
            string result="";
            string str = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
            ArrayList list = array(str);
            for (int i = 0; i < list.Count;i++)
            {
                if (i == list.Count - 1)
                {
                    result += list[i];
                }
                else
                {
                    result += list[i] + ",";
                }
            }
            Console.WriteLine(result);

            Console.ReadKey();
        }

        static ArrayList array(string str)
        {
            ArrayList aimArr = new ArrayList();
            ArrayList strArr = new ArrayList();
            string [] strs=str.Split(',');
            foreach (string s in strs)
            {
                strArr.Add(s);
            }
            for (int i = 0; i < strs.Length; i++)
            {
                if (!aimArr.Contains(strs[i]))
                {
                    aimArr.Add(strs[i]);
                }
            }
            return aimArr;
        }
    }

  //101,102,103,104,105,106,107,108

方法三：使用正则

            string input = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
            input = Regex.Replace(input + ",", @"(?:([^,]+,))(?=.*?\1)", "");
            Console.WriteLine(input.Substring(0,input.Length-1));

public static void Main() 
{ 
string pattern = @"(^189\d{8}$)|(^13\d{9}$)|(^15\d{9}$)"; 
Console.WriteLine("输入号码"); 
string temp = Console.ReadLine(); 
if (System.Text.RegularExpressions.Regex.IsMatch(temp, pattern)) //正则表达式匹配
Console.WriteLine("手机号输入正确！"); 
else 
Console.WriteLine("手机号输入错误！"); 
} 
我也不知道手机的开头到底有多少种···这个应该可以验证大部分了
比如189开头的，130等，159之类