1.定义长度为5的整型数组,输入他们的值,用冒泡排序后输出.
package book1; public class asd { public static void main(String[] args) { // TODO Auto-generated method stub int[] a = {2,6,3,5,1,4}; for (int i = 0; i < a.length-1; i++) { for (int j = 0; j < a.length-1-i; j++) { if(a[j]>a[j+1]){ int b = a[j]; a[j] = a[j+1]; a[j+1] = b; } } } for (int i = 0; i < a.length; i++) { System.out.print(a[i]); } } }
2.定义数组{34,22,35,67,45,66,12,33},输入一个数a,查找在数组中是否存在,如果存在,输出下标,不存在输出"not found"
package book1; import java.util.*; public class asd { public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.println("请输入一个数"); int a = input.nextInt(); boolean flag = false; int[] b = { 34, 22, 35, 67, 45, 66, 12, 33 }; int c = 0; for (int i = 0; i < b.length; i++) { if (b[i] == a) { c = i; System.out.println("下标为" + c); flag = true; } } if (flag == false) { System.out.println("no found"); } } }
3.以矩阵的形式输出一个double型二维数组(长度分别为5、4,值自己设定)的值。
package book1; public class asd { public static void main(String[] args) { double[][] arr = { { 11, 12, 13, 14 }, { 15, 16, 17, 18 }, { 19, 20, 11, 12 }, { 13, 14, 15, 16 }, { 17, 18, 19, 20 } }; for (int i = 0; i < arr.length; i++) { System.out.println(); for (int j = 0; j < arr[i].length; j++) { System.out.print(arr[i][j] + " "); } } } }
4.定义一个二维数组(长度分别为3,4,值自己设定),求该二维数组的最大值.
package book1; public class asd { public static void main(String[] args) { int[][] a = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } }; int max = a[0][0]; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { if (a[i][j] > max) { max = a[i][j]; } } } System.out.println("最大值为" + max); } }