506. Relative Ranks

Given scores of N athletes, find their relative ranks and the people with the top three highest scores, who will be awarded medals: "Gold Medal", "Silver Medal" and "Bronze Medal".
Example 1:

Input: [5, 4, 3, 2, 1]
Output: ["Gold Medal", "Silver Medal", "Bronze Medal", "4", "5"]
Explanation: The first three athletes got the top three highest scores, so they got "Gold Medal", "Silver Medal" and "Bronze Medal". 
For the left two athletes, you just need to output their relative ranks according to their scores.

Note:

• 1.N is a positive integer and won't exceed 10,000.
• 2.All the scores of athletes are guaranteed to be unique.

这道题目的意思是返回数组中每一个元素的排名，不能直接排序这样会打乱每一个元素的原始位置，因为题目上面说数组中的每一个值都是唯一的，所以可以用python的字典方面的找出排序。
这里我使用的是leetcode其他用户给出的java写法，主要是因为里面的lambda新特性。

public String[] findRelativeRanks(int[] nums) {
        
        int pair[][] = new int[nums.length][2];
        for(int i = 0; i < nums.length; i++)
        {
            pair[i][0] = nums[i];
            pair[i][1] = i;
        }
        Arrays.sort(pair,(a,b) -> (b[0] - a[0])); 
        String result[] = new String[nums.length];
        for(int i = 0; i < nums.length; i++)
        {
            if (i == 0)
                result[pair[i][1]] = "Gold Medal";
            else if (i == 1) 
                result[pair[i][1]] = "Silver Medal";
            else if (i == 2)
                result[pair[i][1]] = "Bronze Medal";
            else
                result[pair[i][1]] = (i + 1) + "";
        }
        return result;
    }

上面连接已经给出了详解，我在啰嗦一下pair数值发生变化

10, 0
3, 1
8, 2
9, 3
4, 4
排序后
10, 0
9, 3
8, 2
4, 4
3, 1

详细的lambda介绍可见这里