Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
C++实现代码:
#include<iostream> #include<new> #include<vector> #include<cmath> using namespace std; //Definition for binary tree struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: bool isBalanced(TreeNode *root) { if(root==NULL) return true; int lhigh=maxDepth(root->left); int rhigh=maxDepth(root->right); if(abs(lhigh-rhigh)>1) return false; return isBalanced(root->left)&&isBalanced(root->right); } int maxDepth(TreeNode *root) { if(root) { if(root->left==NULL&&root->right==NULL) return 1; int leftDepth=maxDepth(root->left); int rightDepth=maxDepth(root->right); return leftDepth>= rightDepth ?(leftDepth+1):(rightDepth+1); } return 0; } void createTree(TreeNode *&root) { int i; cin>>i; if(i!=0) { root=new TreeNode(i); if(root==NULL) return; createTree(root->left); createTree(root->right); } } }; int main() { Solution s; TreeNode *root; s.createTree(root); cout<<s.maxDepth(root); cout<<endl; cout<<s.isBalanced(root)<<endl; }