Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
这个题应该就是求子串的问题,改进的方法是kmp算法。
朴素算法的C++代码如下:
#include<iostream> #include<cstring> using namespace std; class Solution { public: int strStr(char *haystack, char *needle) { if(strlen(haystack)<strlen(needle)) return -1; size_t i,j,k; for(i=0;i<=(strlen(haystack)-strlen(needle));i++) { k=i; for(j=0;j<strlen(needle);j++) { if(haystack[k]==needle[j]) k++; else break; } if(j==strlen(needle)) return i; } if(j==strlen(needle)) return i; return -1; } }; int main() { Solution s; char s1[]="swwssswsss"; char s2[]="sss"; cout<<s.strStr(s1,s2)<<endl; }
运行结果: