• python笔记04-----字典、元组、集合操作


    1.字典

    是一种key-value的数据类型,使用就像字典

    无序的因为无下标

    创建一个字典:

    info = {
        'stu1':'qq',
        'stu2':'ww',
        'stu3':'ee',
    }

    print(info)

    输出结果

    {'stu1': 'qq', 'stu2': 'ww', 'stu3': 'ee'}

    1.1增改

    有就修改,没有就增加

    info['stu1'] = "gg"
    info['sut4'] = 'hhh'
    print(info)
    {'stu1': 'gg', 'stu2': 'ww', 'stu3': 'ee', 'sut4': 'hhh'}

    1.2删除

    del,pop()删除指定

     del info['stu1']

    print(info)

    {'stu2': 'ww', 'stu3': 'ee', 'sut4': 'hhh'}
    info.pop('stu2')
    print(info)

    {'stu3': 'ee', 'sut4': 'hhh'}

    popitem()随机删除

    info.popitem()
    print(info)

    {'stu3': 'ee'}

    1.3查询

    get(‘keys’)查询key,有就返回value,如果没有就返回none

    print(info.get('stu1'))

    qq

    1.4字典嵌套

    values(),keys() 查询key和values

    city = {
        "北京":["东城","西城","大悦城"],
        "上海":["虹桥","上海动物园","东方明珠"],
        "浙江":["杭州","温州","横店"],
    }

    #打印values
    print(city.values())

    dict_values([['东城', '西城', '大悦城'], ['虹桥', '上海动物园', '东方明珠'], ['杭州', '温州', '横店']])

    #打印key
    print(city.keys())

    dict_keys(['北京', '上海', '浙江'])

    setdefault()方法-增

    city.setdefault("USA",{"美国":["华盛顿","洛杉矶","环球影城"]})

    print(city)

    {'北京': ['东城', '西城', '大悦城'], '上海': ['虹桥', '上海动物园', '东方明珠'], '浙江': ['杭州', '温州', '横店'], 'USA': {'美国': ['华盛顿', '洛杉矶', '环球影城']}}

    dir1.update(dir2)更新

    info = {
        'stu1':'qq',
        'stu2':'ww',
        'stu3':'ee',
    }
    b = {
        'stu1':'qwe',
        1:3,
        2:5,
    }
    info.update(b)
    print(info)

    {'stu1': 'qwe', 'stu2': 'ww', 'stu3': 'ee', 1: 3, 2: 5}

    items()字典转成列表

    print(info.items())

    dict_items([('stu1', 'qq'), ('stu2', 'ww'), ('stu3', 'ee')])

    fromkeys([1],”str”)初始化一个新的字典,每个value赋值相同

    print(dict.fromkeys([6,7,8],"yrdy"))

    {6: 'yrdy', 7: 'yrdy', 8: 'yrdy'}

    修改用fromkeys初始化出来的字典其中的一层,都会跟着改

    c = dict.fromkeys([6,7,8],[1,{"name":"wsy"},555])
    print(c)
    c[7][1]['name'] = "jack"
    print(c)

    {6: [1, {'name': 'wsy'}, 555], 7: [1, {'name': 'wsy'}, 555], 8: [1, {'name': 'wsy'}, 555]}

    {6: [1, {'name': 'jack'}, 555], 7: [1, {'name': 'jack'}, 555], 8: [1, {'name': 'jack'}, 555]}

    1.5字典的循环

    city = {
    "北京":["东城","西城","大悦城"],
    "上海":["虹桥","上海动物园","东方明珠"],
    "浙江":["杭州","温州","横店"],
    }

    for i in city: #高效
    print(i,city[i])

    for v,k in city.items(): #低效
    print(v,k)

    北京 ['东城', '西城', '大悦城']
    上海 ['虹桥', '上海动物园', '东方明珠']
    浙江 ['杭州', '温州', '横店']

    2.元组

    只能查

    列表元组互相转换

    names = ("wsy","wwsy","jack")
    p = list(names)
    print(p)

    ['wsy', 'wwsy', 'jack']

    转换回来

    names = ("wsy","wwsy","jack")
    p = list(names)
    q = tuple(p)
    print(q)

    ('wsy', 'wwsy', 'jack')

    index方法-返回索引位置下标

    names = ("wsy","wwsy","jack")
    p = names.index("jack")
    print(p)

    2

    count方法-搜索字符,返回个数

    names = ("wsy","wwsy","jack")
    p = names.count("wsy")
    print(p)

    1

    3.集合

    集合中只包含数字

    list_1 = [1,4,5,7,3,6,7,9]
    print(list_1)
    list_1 = set(list_1)
    list_2 =set([2,6,0,66,22,8,4])
    print(list_1,list_2)

    [1, 4, 5, 7, 3, 6, 7, 9]
    {1, 3, 4, 5, 6, 7, 9} {0, 2, 66, 4, 6, 8, 22}

    intersection()方法-求交集

    print(list_1.intersection(list_2))
    print(list_1 & list_2)

    union()方法-求并集

    print(list_1.union(list_2))
    print(list_2 | list_1)

    difference()方法-求差集

    #差集 in list_1 but not in list_2
    print(list_1.difference(list_2))
    print(list_2.difference(list_1))

    判断是否是子集

    list_3 = set([1,3,7])
    print(list_3.issubset(list_1))
    print(list_1.issuperset(list_3))

    symmetric_difference()方法求对称差集

    print(list_1.symmetric_difference(list_2))

    print(list_1 ^ list_2)

    pop()方法随机删除

    print(list_1.pop())

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  • 原文地址:https://www.cnblogs.com/wsy1030/p/8990802.html
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