• POJ 2240


    POJ2240

    题目大意:求负环

    解:尼玛这有自环的,所以要u := q[head之后马上取消visit标记

    View Code
      1 const
    2 maxn=30;
    3 bilibili=maxlongint >> 1;
    4 type
    5 data=record
    6 dest, next: longint;
    7 cost: double;
    8 end;
    9 var
    10 edge: array[1..maxn*maxn]of data;
    11 a: array[1..maxn]of string;
    12 vect: array[1..maxn]of longint;
    13 dist: array[1..maxn]of double;
    14 s, tot, n, m: longint;
    15 flag : boolean;
    16 function find(x: string): longint;
    17 var
    18 i: longint;
    19 begin
    20 for i := 1 to n do
    21 if a[i]=x then exit(i);
    22 end;
    23
    24 procedure add(x, y: longint; z: double);
    25 begin
    26 inc(tot);
    27 with edge[tot] do
    28 begin
    29 dest := y;
    30 cost := z;
    31 next := vect[x];
    32 vect[x] := tot;
    33 end;
    34 end;
    35
    36 procedure init;
    37 var
    38 i, j, x, y, k: longint;
    39 z: double;
    40 c: char;
    41 st: string;
    42 begin
    43 inc(s);
    44 readln(n);
    45 if n=0 then
    46 begin
    47 close(input);
    48 close(output);
    49 halt;
    50 end;
    51 fillchar(vect, sizeof(vect), 0);
    52 flag := false;
    53 tot := 0;
    54
    55 for i := 1 to n do readln(a[i]);
    56 readln(m);
    57 for i := 1 to m do
    58 begin
    59 read(c);
    60 st := '';
    61 while c<>' ' do
    62 begin
    63 st := st + c;
    64 read(c);
    65 end;
    66 x := find(st);
    67 st := '';
    68 read(z);
    69 read(c);
    70 st := '';
    71 read(c);
    72 while not(eoln) do
    73 begin
    74 st := st + c;
    75 read(c);
    76 end;
    77 st := st + c;
    78 y := find(st);
    79 add(x, y, z);
    80 readln;
    81 end;
    82 end;
    83
    84 procedure spfa(b, e: longint);
    85 var
    86 q: array[1..maxn+10]of longint;
    87 key: array[1..maxn]of longint;
    88 visit: array[1..maxn]of boolean;
    89 head, tail, i, u: longint;
    90 begin
    91 fillchar(dist, sizeof(dist), 0);
    92 fillchar(visit, sizeof(visit), 0);
    93 fillchar(key, sizeof(key), 0);
    94 head := 0;
    95 tail := 1;
    96 q[1] := b;
    97 dist[b] := 1000;
    98 visit[b] := true;
    99 while head<>tail do
    100 begin
    101 head := head mod (maxn+10) +1;
    102 u := q[head];
    103 visit[u] := false;
    104 if key[u]>=n then
    105 begin
    106 flag := true;
    107 exit;
    108 end;
    109 inc(key[u]);
    110 i := vect[u];
    111 while i<>0 do
    112 with edge[i] do
    113 begin
    114 if dist[u] * cost>dist[dest] then
    115 begin
    116 dist[dest] := dist[u] * cost;
    117 if not visit[dest] then
    118 begin
    119 visit[dest] := true;
    120 tail := tail mod (maxn+10) +1;
    121 q[tail] := dest;
    122 end;
    123 end;
    124 i := next;
    125 end;
    126 end;
    127 flag := false;
    128 end;
    129
    130 procedure print;
    131 begin
    132 write('Case ');
    133 write(s, ': ');
    134 if flag then writeln('Yes')
    135 else writeln('No');
    136 end;
    137
    138 procedure main;
    139 var
    140 i, j, k: longint;
    141 begin
    142 s := 0;
    143 while true do
    144 begin
    145 init;
    146 readln;
    147 i := 0;
    148 while (not flag)and(i<n) do
    149 begin
    150 inc(i);
    151 spfa(i, i);
    152 end;
    153 print;
    154 end;
    155 end;
    156
    157 begin
    158 assign(input,'aaa.in'); reset(input);
    159 main;
    160 //close(input);
    161 end.



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  • 原文地址:https://www.cnblogs.com/wmzisfoolish/p/2435157.html
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