Nothing to fear
种一棵树最好的时间是十年前，其次是现在！
那些你早出晚归付出的刻苦努力，你不想训练，当你觉的太累了但还是要咬牙坚持的时候，那就是在追逐梦想，不要在意终点有什么，要享受路途的过程，或许你不能成就梦想，但一定会有更伟大的事情随之而来。 mamba out~
2020.6.28
人一我十，人十我百，追逐青春的梦想，怀着自信的心，永不言弃！
GPLT-L2-009 抢红包
- 如果出现double类型进行比较大小可能是坑，尽可能想办法根据题意看能否
转化为int类型进行比较 - 使用vecotr容器在pat中更好使
#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <vector>
using namespace std;
const int N = 10005;
int n;
struct node{
int id;
int money; //元位单位
int cnt;
};
bool vis[N];
bool cmp(node a,node b)
{
if(a.money != b.money)return a.money > b.money;
else if(a.cnt != b.cnt)return a.cnt > b.cnt;
else return a.id < b.id;
}
int main()
{
cin >> n;
vector<node> ans(n + 1);
for(int who = 1;who <= n;who ++)
{
int k , id ,mount;
cin >> k;
ans[who].id = who;
for(int i = 0;i < k;i ++)
{
cin >> id >> mount;
if(!vis[id])
{
ans[id].money += mount ;
ans[who].money -= mount;
ans[id].cnt++;
}
vis[id] = true;
}
memset(vis , 0 , sizeof vis);
}
sort(ans.begin() + 1, ans.end(), cmp);
for(int i = 1;i <= n;i ++)
{
printf("%d %.2f
",ans[i].id, (double)ans[i].money * 1.0 / 100);
}
return 0;
}
GPLT -L2-010 排座位
思路： 根据输入的信息建立图模型
利用一个二维数组直接存两个客人之间的关系。
如果两个人关系为敌人时，需要检测一下两个人是否存在共同的朋友
此时用dfs去检查一下从一个点能够只走关系为1的边走到目标那里即可
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <string>
#include <vector>
using namespace std;
const int N = 105;
vector<int> mapp[N];
int g[N][N];
int n , m , k;
bool vis[N];
void check(int s, int t, bool &flag)
{
if(s == t){
flag = true;
return;
}
for(int i = 0;i < mapp[s].size();i ++)
{
int next = mapp[s][i];
if(!vis[next] && g[s][next] == 1 && !flag)
{
vis[next] = 1;
check(next , t , flag);
vis[next] = 0;
}
}
}
int main()
{
cin >> n >> m >> k;
for(int i = 0;i < m;i ++)
{
int a , b , c;
scanf("%d %d %d",&a , & b, &c);
g[a][b] = c;g[b][a] = c;
mapp[a].push_back(b);
mapp[b].push_back(a);
}
for(int i = 0;i < k;i ++)
{
int a, b;
scanf("%d %d",&a , &b);
if(g[a][b] == 1)
printf("No problem
");
if(g[a][b] == 0)
printf("OK
");
if(g[a][b] == -1)
{
bool flag = false;
check(a , b , flag);
if(flag)
{
printf("OK but...
");
}else printf("No way
");
}
}
return 0;
}
GPLT-L2-011 玩转二叉树
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
#include <queue>
using namespace std;
struct node{
int val;
struct node *left = NULL;
struct node *right = NULL;
};
int n;
vector<int> in , pre, level;
int find(int x)
{
for(int i = 0;i < in.size();i++)
{
if(x == in[i])return i;
}
}
node* build(int x,int y,int p,int q)
{
if(x > y || p > q)return NULL;
int i = find(pre[x]); // 在中序遍历中找到当前先序区间中的第一个
int k = i - p;
node *now = new node;
now->val = pre[x];
now->right = build(x + 1, x + k, p , i - 1);
now->left = build(x + k + 1, y, i + 1, q);
return now;
}
void bfs(node *root)
{
queue<node*> q;
q.push(root);
while(!q.empty())
{
node *now = q.front();q.pop();
level.push_back(now->val);
if(now->left != NULL)q.push(now->left);
if(now->right != NULL)q.push(now->right);
}
return;
}
int main()
{
cin >> n;
in.resize(n),pre.resize(n);
for(int i = 0;i < n;i ++)
cin >> in[i];
for(int i = 0;i < n;i ++)
cin >> pre[i];
node *tree = build(0, n-1,0,n-1);
bfs(tree);
for(int i = 0;i < n;i ++)
{
if(i == 0)printf("%d",level[i]);
else printf(" %d",level[i]);
}
return 0;
}
650Div3 A
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#include <cstring>
#include <vector>
#include <cassert>
#include <string>
#include <iomanip>
#include <cmath>
#include <ctime>
#define SIS std::ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
#define lowbit(x) (x & -x)
using namespace std;
typedef long long ll;
const int MAX = 1e+9;
int t;
void slove()
{
ll x , y , n;
cin >> x >> y >> n;
ll l = 0, r = MAX;
while(l < r)
{
ll mid = l + r + 1>> 1;
if(mid * x + y <= n)l = mid;
else r = mid - 1;
}
cout << l * x + y << endl;
}
int main()
{
#ifdef LOCAL
auto start_time = clock();
cerr << setprecision(3) << fixed; // 在iomanip中
#endif
SIS;
cin >> t;
while(t--)
{
slove();
}
#ifdef LOCAL
auto end_time = clock();
cerr << "Execution time: " << (end_time - start_time) * (int)1e3 / CLOCKS_PER_SEC << " ms
";
#endif
}
650Div3 B
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#include <cstring>
#include <vector>
#include <cassert>
#include <string>
#include <iomanip>
#include <cmath>
#include <ctime>
#define SIS std::ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
#define lowbit(x) (x & -x)
using namespace std;
typedef long long ll;
const int MAX = 0x7ffffff;
int t;
void slove()
{
int n;
cin >> n;
int ans = 0;
while(n != 1)
{
while(n % 6 == 0)
{
n /= 6;
ans++;
}
int cnt = 0;
while(n % 6 != 0 && n != 1)
{
cnt++;n *= 2;
if(cnt > 1){
cout << -1 << endl;
return;
}
ans++;
}
}
cout << ans << endl;
}
int main()
{
#ifdef LOCAL
auto start_time = clock();
cerr << setprecision(3) << fixed; // 在iomanip中
#endif
SIS;
cin >> t;
while(t--)
{
slove();
}
#ifdef LOCAL
auto end_time = clock();
cerr << "Execution time: " << (end_time - start_time) * (int)1e3 / CLOCKS_PER_SEC << " ms
";
#endif
}
650Div3 C
手生的一批
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#include <cstring>
#include <vector>
#include <cassert>
#include <string>
#include <iomanip>
#include <cmath>
#include <ctime>
#include <map>
#define SIS std::ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
#define lowbit(x) (x & -x)
using namespace std;
typedef long long ll;
const int MAX = 0x7ffffff;
int t , n;
void slove()
{
int n;
string s;
cin >> n >> s;
int ans = 0 , cnt = 0;
for(char c : s)
{
cnt += (c == ')' ? 1 : -1);
ans = max(ans , cnt);
}
cout << ans << endl;
}
int main()
{
#ifdef LOCAL
auto start_time = clock();
cerr << setprecision(3) << fixed; // 在iomanip中
#endif
SIS;
cin >> t;
while(t--)
{
slove();
}
#ifdef LOCAL
auto end_time = clock();
cerr << "Execution time: " << (end_time - start_time) * (int)1e3 / CLOCKS_PER_SEC << " ms
";
#endif
}