• 经纬度转换 C#类


    经纬度转换 C#类

    public class GCJ2WGSUtils {
        // 输入GCJ经纬度 转WGS纬度
        public static double WGSLat(double lat, double lon) {
            double PI = 3.14159265358979324;// 圆周率
            double a = 6378245.0;// 克拉索夫斯基椭球参数长半轴a
            double ee = 0.00669342162296594323;// 克拉索夫斯基椭球参数第一偏心率平方
            double dLat = transformLat(lon - 105.0, lat - 35.0);
            double radLat = lat / 180.0 * PI;
            double magic = Math.sin(radLat);
            magic = 1 - ee * magic * magic;
            double sqrtMagic = Math.sqrt(magic);
            dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * PI);
            return (lat - dLat);
        }
    
        // 输入GCJ经纬度 转WGS经度
        public static double WGSLon(double lat, double lon) {
            double PI = 3.14159265358979324;// 圆周率
            double a = 6378245.0;// 克拉索夫斯基椭球参数长半轴a
            double ee = 0.00669342162296594323;// 克拉索夫斯基椭球参数第一偏心率平方
            double dLon = transformLon(lon - 105.0, lat - 35.0);
            double radLat = lat / 180.0 * PI;
            double magic = Math.sin(radLat);
            magic = 1 - ee * magic * magic;
            double sqrtMagic = Math.sqrt(magic);
            dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * PI);
            return (lon - dLon);
        }
    
        // 转换经度所需
        public static double transformLon(double x, double y) {
            double PI = 3.14159265358979324;// 圆周率
            double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x));
            ret += (20.0 * Math.sin(6.0 * x * PI) + 20.0 * Math.sin(2.0 * x * PI)) * 2.0 / 3.0;
            ret += (20.0 * Math.sin(x * PI) + 40.0 * Math.sin(x / 3.0 * PI)) * 2.0 / 3.0;
            ret += (150.0 * Math.sin(x / 12.0 * PI) + 300.0 * Math.sin(x / 30.0 * PI)) * 2.0 / 3.0;
            return ret;
        }
    
        // 转换纬度所需
        public static double transformLat(double x, double y) {
            double PI = 3.14159265358979324;// 圆周率
            double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x));
            ret += (20.0 * Math.sin(6.0 * x * PI) + 20.0 * Math.sin(2.0 * x * PI)) * 2.0 / 3.0;
            ret += (20.0 * Math.sin(y * PI) + 40.0 * Math.sin(y / 3.0 * PI)) * 2.0 / 3.0;
            ret += (160.0 * Math.sin(y / 12.0 * PI) + 320 * Math.sin(y * PI / 30.0)) * 2.0 / 3.0;
            return ret;
        }
    }
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  • 原文地址:https://www.cnblogs.com/wishit/p/15501955.html
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