• STL


     1 #include<iostream>
     2 #include<list>
     3 
     4 using namespace std;
     5 // list 构造函数
     6 void test01()
     7 {
     8     list<int> lst1;
     9     lst1.push_back(10);
    10     lst1.push_back(20);
    11     lst1.push_back(30);
    12     list<int> lst2(lst1);//拷贝构造函数
    13     list<int> lst3(5, 10);//构造函数
    14     list<int> lst4;
    15     lst4.assign(lst3.begin(), lst3.end());
    16 }
    17 
    18 // list 数据元素的插入与删除操作
    19 void test02()
    20 {
    21     list<int> lst1;
    22     lst1.push_back(30);
    23     lst1.push_front(20);//20 30
    24     lst1.insert(lst1.begin(), 10);//10 20 30  // 相当于 push_front
    25     lst1.insert(lst1.end(), 40);//10 20 30 40 // 相当于 push_back
    26     list<int>::iterator itr = lst1.begin();
    27     itr++;
    28     itr++;
    29     lst1.insert(itr, 999);//10 20 999 30 40
    30     lst1.push_back(999); //10 20 999 30 40 999
    31     auto itr_ = lst1.begin();
    32     itr_++;
    33     lst1.erase(lst1.begin(), itr_);// [ , )左闭右开  20 999 30 40 999
    34     lst1.remove(999);//删除容器中所有值为999的元素    20 30 40 
    35 }
    36 int main()
    37 {
    38     test01();
    39     test02();
    40     return 1;
    41 }

       链表每个节点都有一个指针,结果是:链表插入与删除效率比线性表高,但是内存开销大,同时链表节点遍历相对线性表慢。

    链表的c语言实现版本:

      1 #include<iostream>
      2 #include<set>
      3 using namespace std;
      4 
      5 class Node
      6 {
      7 public:
      8     int data_;//数据阈
      9     Node* next_;//指针阈
     10 public:
     11     Node():data_(-1), next_(nullptr) {}
     12 };
     13 
     14 class List
     15 {
     16 public:
     17     List()
     18     {
     19         this->head_ = new Node();// 不分配空间,下面赋值是不合理的!
     20                                  //this->head_->data_ = 0;//多余?
     21         this->head_->next_ = nullptr;
     22         this->size_ = 0;
     23     };
     24     void insert(int pos, int value);
     25     void remove(int pos);
     26     int get_reverse_element(int reverse_pos);//链表中倒数第k个节点
     27     void reverse();
     28 
     29     int operator[](int i);
     30     void print();
     31     ~List();
     32 
     33 
     34 public:
     35     Node* head_;
     36     int size_;//维护一个size
     37 };
     38 //在第pos个元素前一个位置插入(创建、找到位置、入链表)
     39 void List::insert(int pos, int value)
     40 {
     41     if (pos < 0 || pos > size_)
     42         return;
     43 
     44     //创建新的节点接受数据
     45     Node* newnode = new Node();
     46     newnode->data_ = value;
     47     //cout << "newnode->data_ = " << *newnode->data_ << endl;
     48     newnode->next_ = nullptr;
     49 
     50     //利用辅助指针找到pos前一个节点
     51     // 其实这里不断next,无非就是希望p_curr = nullptr
     52     // 然后56行 让newnode->next_  = nullptr(这个nullptr是从head_->next 传过来的);也就是尾部插入嘛
     53     // 而循环链表 同理 让newnode->next_  = &(head_)(这个 &(head_) 是从head_->next 传过来的);
     54     Node* p_curr = head_;
     55     for (int i = 0; i < pos; i++) //这个for循环本质上是head_->next_->next_......
     56     {
     57         p_curr = p_curr->next_;
     58     }
     59     //现在p_curr就是pos前一个节点的指针阈
     60     //新节点入链表
     61     newnode->next_ = p_curr->next_;//右边
     62     p_curr->next_ = newnode;//左边
     63     size_++;
     64 }
     65 
     66 void List::remove(int pos)
     67 {
     68     if (pos < 0 || pos > size_)
     69     {
     70         return;
     71     }
     72     Node* p_curr = head_;
     73     for (int i = 0; i < pos; i++)// 3
     74     {
     75         p_curr = p_curr->next_;
     76     }
     77     p_curr->next_ = p_curr->next_->next_;
     78     size_--;
     79 }
     80 
     81 //链表中倒数第k个节点
     82 int List::get_reverse_element(int reverse_pos)
     83 {
     84     int pos = size_ - reverse_pos;
     85     Node* p_curr = head_;
     86     for (int i = 0; i < pos; i++)
     87     {
     88         p_curr = p_curr->next_;
     89     }
     90     return p_curr->data_;
     91 }
     92 
     93 //反转链表
     94 void List::reverse()
     95 {
     96     // head   -> 1 -> 2 -> 3 -> 4 -> nullptr
     97     //nullptr <- 1 <- 2 <- 3 <- 4
     98 
     99     Node* p_curr = head_->next_;
    100     Node* p_prev = nullptr;
    101     while (p_curr != nullptr)
    102     {
    103         Node* p_next = p_curr->next_;
    104         if(p_curr->next_ == nullptr)
    105         {
    106             head_->next_ = p_curr;
    107         }
    108         p_curr->next_ = p_prev;
    109         p_prev = p_curr;
    110         p_curr = p_next;
    111     }
    112 }
    113 
    114 int List::operator[](int i)
    115 {
    116     Node* p_curr = head_;
    117     int count = 0;
    118     while (count <= i)
    119     {
    120         p_curr = p_curr->next_;
    121         count++;
    122     }
    123     return p_curr->data_;
    124 }
    125 void List::print()
    126 {
    127     if (size_ == 0)
    128     {
    129         cout << "size = 0" << endl;
    130         return;
    131     }
    132     //遍历
    133     Node* p_curr = head_->next_;//【注意这里next】
    134     while (p_curr != nullptr)
    135     {
    136         cout << p_curr->data_ << " ";
    137         p_curr = p_curr->next_;
    138     }
    139     cout << endl;
    140 }
    141 List::~List()
    142 {
    143     while (size_ != 0)
    144     {
    145         Node* p_curr = head_;
    146         for (int i = 0; i < (size_ - 1); i++)// 012345 i < 5
    147         {
    148             p_curr = p_curr->next_;//for循环执行完,p_curr指向4
    149         }
    150         delete p_curr->next_;//删除最后一个元素
    151         p_curr->next_ = nullptr;//末尾元素 空指针
    152         size_--;
    153         print();
    154     }
    155     delete head_; //【这个容易忘记!】
    156     cout << "delete!" << endl;
    157 }
    158 
    159 //合并两个排序链表
    160 void mergeLists(List& list3, List& list4, List& list34)
    161 {
    162     Node* p_curr3 = list3.head_->next_;
    163     Node* p_curr4 = list4.head_->next_;
    164     Node* p_curr34 = list34.head_->next_;
    165     int location = 0;
    166     while ((p_curr3 != nullptr) || (p_curr4 != nullptr))
    167     {
    168         if ((p_curr3 != nullptr) && (p_curr4 != nullptr))
    169         {
    170             if (p_curr3->data_ < p_curr4->data_)
    171             {
    172                 list34.insert(location, p_curr3->data_);
    173                 location++;
    174                 list34.insert(location, p_curr4->data_);
    175                 location++;
    176             }
    177             else
    178             {
    179                 list34.insert(location, p_curr4->data_);
    180                 location++;
    181                 list34.insert(location, p_curr3->data_);
    182                 location++;
    183             }
    184             p_curr3 = p_curr3->next_;
    185             p_curr4 = p_curr4->next_;
    186         }
    187         else if ((p_curr3 != nullptr) && (p_curr4 == nullptr))
    188         {
    189             list34.insert(location, p_curr3->data_);
    190             location++;
    191             p_curr3 = p_curr3->next_;
    192         }
    193         else if ((p_curr3 == nullptr) && (p_curr4 != nullptr))
    194         {
    195             list34.insert(location, p_curr4->data_);
    196             location++;
    197             p_curr4 = p_curr4->next_;
    198         }
    199     }
    200 }
    201 
    202 
    203 int main()
    204 {
    205     List list1;
    206     //插入
    207     for (int i = 0; i < 15; i++)
    208     {
    209         list1.insert(i, i);
    210     }
    211 
    212     //删除
    213     list1.remove(10);
    214     list1.remove(5);
    215     //打印
    216     list1.print();
    217     list1.reverse();
    218     list1.print();
    219     //访问倒数元素
    220     for (int i = 1; i < 4; i++)
    221     {
    222         cout << "倒数第" << i << "个元素是:" << list1.get_reverse_element(i) << endl;
    223     }
    224     list1.insert(2, 9999);
    225     //重载符[]
    226     for (int i = list1.size_ - 1; i >= 0; i--)
    227     {
    228         cout << list1[i] << " ";
    229     }
    230     cout << endl;
    231     List list2;
    232     list2.insert(0, 10);
    233     list2.insert(1, 20);
    234     list2.insert(2, 30);
    235     list2.print();
    236     int size2 = list2.size_;
    237 
    238     //合并两个排序链表
    239     List list3, list4;
    240     for (int i = 0; i < 5; i++)
    241     {
    242         list3.insert(i, 2 * i);
    243         list4.insert(i, 2 * i + 1);
    244     }
    245     list4.insert(5, 12);
    246     list4.insert(6, 21);
    247     list3.print();
    248     list4.print();
    249 
    250     List list34;
    251     mergeLists(list3, list4, list34);
    252     list34.print();
    253 
    254 
    255     return 1;
    256 }
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  • 原文地址:https://www.cnblogs.com/winslam/p/9416335.html
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