• 牛客国庆集训派对Day3 I Metropolis


    Metropolis

    思路:

    多源点最短路

    只要两个不同源点的最短路相遇,我们就更新两个源点的答案

    代码:

    #pragma GCC optimize(2)
    #pragma GCC optimize(3)
    #pragma GCC optimize(4)
    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pli pair<LL, int>
    #define pii pair<int, int>
    #define piii pair<pli, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e5 + 100;
    const LL INF = 0x7f7f7f7f7f7f7f7f;
    vector<pii> g[N];
    priority_queue<piii, vector<piii>, greater<piii> > q;
    pli d[N];
    LL dis[N];
    vector<int> st;
    void dijkstra() {
        while(!q.empty()) {
            piii now = q.top();
            q.pop();
            int u = now.fi.se;
            if(d[u].fi < now.fi.fi) continue;
            for (pii t : g[u]) {
                int v = t.fi;
                int w = t.se;
                if(d[v].fi > w + now.fi.fi) {
                        d[v].se = now.se;
                        d[v].fi = w + now.fi.fi;
                        q.push(piii{{d[v].fi, v}, now.se});
                }
                if(d[v].se && d[v].se != now.se) {
                    int u1 = d[v].se;
                    int u2 = now.se;
                    dis[u1] = min(dis[u1], d[v].fi+now.fi.fi + w);
                    dis[u2] = min(dis[u2], d[v].fi+now.fi.fi + w);
                }
            }
        }
    }
    int main() {
        int n, m, p, u, v, w;
        scanf("%d %d %d", &n, &m, &p);
        for (int i = 1; i <= n; i++) d[i].fi = INF, d[i].se = 0, dis[i] = INF;
        for (int i = 0; i < p; i++) scanf("%d", &u), d[u] = pii{0, u}, q.push(piii{{0, u}, u}), st.pb(u);
        for (int i = 0; i < m; i++) {
            scanf("%d %d %d", &u, &v, &w);
            g[u].pb(pii{v, w});
            g[v].pb(pii{u, w});
        }
        dijkstra();
        for (int x : st) printf("%lld ", dis[x]);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/widsom/p/9742074.html
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