• SPOJ 刷题记录


    按点赞数降序

    297 二分 

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5;
    int a[N], c, n;
    bool check(int d) {
        int pre = a[1], cnt = 1;
        for(int i = 2; i <= n; i++) {
            if((a[i] - pre) >= d) {
                pre = a[i];
                cnt++;    
            }
        }
        return cnt >= c;
    }
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &c);
            for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
            sort(a+1, a+1+n);
            int l = 1, r = 1e9+5, m = (l+r) >> 1;
            while(l < r) {
                if(check(m)) l = m;
                else r = m - 1;
                m = (l+r+1) >> 1;
                //cout << l <<" " << r << endl;
            }
            printf("%d
    ", m);
        }
        return 0;
    }
    View Code

    2 区间素数筛

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5;
    bool notp_big[N], notp_small[N];
    void prime(LL a, LL b) {
        mem(notp_big, false);
        if(a==1) notp_big[0] = true;
        for (LL i = 2; i*i <= b; i++) {
            if(!notp_small[i]) {
                for (LL j = i+i; j*j <= b; j += i) notp_small[j] = true;
                for (LL j = max(2LL, (a+i-1)/i)*i; j <= b; j += i)notp_big[j-a] = true;
            }
        }
    }
    int main() {
        int T, n, m;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            prime(n, m);
            for (int i = n; i <= m; i++) if(!notp_big[i-n])printf("%d
    ", i);
        }
        return 0;
    }
    View Code

    346 dp 小于5e6预处理,大于5e6递归

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 5e6+5;
    int dp[N];
    map<int, LL>mp;
    LL f(int n) {
        if(n <= 5e6) return dp[n];
        else if(mp[n] != 0) return mp[n];
        return max((LL)n, f(n/2)+f(n/3)+f(n/4));
    }
    int main() {
        int n;
        dp[0]=0;
        dp[1]=1;
        for (int i = 2; i < N; i++) {
            dp[i] = max(i, dp[i/2]+dp[i/3]+dp[i/4]);
        }
        while(~ scanf("%d", &n)) {
            mp.clear();
            printf("%lld
    ", f(n));
        }
        return 0;
    }
    View Code

    394 dp 注意0的情况

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 5555;
    char s[N];
    LL dp[N];
    int main() {
        while(~scanf("%s", s+1)) {
            //printf("%s
    ", s+1);
            if(s[1] == '0')break;
            dp[0] = dp[1] = 1;
            int n = strlen(s+1);
            for (int i = 2; i <= n; i++) {
                if(s[i-1] != '0') {
                    int t = (s[i-1]-'0')*10 + s[i]-'0';
                    //cout << t << endl;
                    if(t <= 26) {
                        if(s[i] != '0')dp[i] = dp[i-1] + dp[i-2];
                        else dp[i] = dp[i-2];
                    }
                    else dp[i] = dp[i-1];
                }
                else dp[i] = dp[i-1];
            }
            printf("%lld
    ", dp[n]);
        }
        return 0;
    }
    View Code

    1043 线段数区间合并,lv记录这段区间以左端点为起点的最大和,rv同理

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 5e4 + 5;
    const int INF = 0x7f7f7f7f;
    struct Tree {
        int sum, lv, rv, ans;
    }tree[N<<2];
    void push_up(int rt) {
        tree[rt].sum = tree[rt<<1].sum + tree[rt<<1|1].sum;
        tree[rt].lv = max(tree[rt<<1].lv, tree[rt<<1].sum + tree[rt<<1|1].lv);
        tree[rt].rv = max(tree[rt<<1|1].rv, tree[rt<<1|1].sum + tree[rt<<1].rv);
        tree[rt].ans = max(tree[rt<<1].rv + tree[rt<<1|1].lv, max(tree[rt<<1].ans, tree[rt<<1|1].ans));
    }
    void build(int rt, int l, int r) {
        if(l == r) {
            scanf("%d", &tree[rt].ans);
            tree[rt].lv = tree[rt].rv = tree[rt].sum = tree[rt].ans;
            return ;
        }
        int m = (l+r) >> 1;
        build(ls);
        build(rs);
        push_up(rt);
    }
    Tree query(int L, int R, int rt, int l, int r) {
        if(L <= l && r <= R) return tree[rt];
        int m = (l + r) >> 1;
        if(R <= m) return query(L, R, ls);
        else if(L > m) return query(L, R, rs);
        Tree lft = query(L, R, ls);
        Tree rit = query(L, R, rs);
        int sum = lft.sum+rit.sum;
        int lv = max(lft.lv, lft.sum+rit.lv);
        int rv = max(rit.rv, rit.sum+lft.rv);
        int ans = max(lft.rv+rit.lv, max(lft.ans, rit.ans));
        return Tree{sum, lv, rv, ans};
    }
    int main() {
        int n, m, x, y;
        scanf("%d", &n);
        build(1, 1, n);
        scanf("%d", &m);
        while(m --) {
            scanf("%d%d", &x, &y);
            Tree res = query(x, y, 1, 1, n);
            printf("%d
    ", res.ans);
        }
        return 0;
    }
    View Code

     6256 普通的逆序数,不过我使用了最近学的方法,从大到小加入位置,跑的比较优秀

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e5 + 5; 
    pii a[N];
    int bit[N], n;
    void add(int x, int a) {
        while(x <= n) bit[x] += a, x += x&-x; 
    } 
    int query(int x) {
        int ans = 0;
        while(x) ans += bit[x], x -= x&-x;
        return ans;
    }
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%d", &n);
            for (int i = 1; i <= n; i++) {
                scanf("%d", &a[i].fi);
                a[i].se = i;
            }
            sort(a+1, a+1+n);
            mem(bit, 0);
            LL ans = 0;
            for(int i = n; i >= 1; i--) {
                ans += query(a[i].se);
                //cout <<".............."<< ans << endl;
                add(a[i].se, 1);
            }
            printf("%lld
    ", ans);
        }
        return 0;
    }
     
    View Code

     5 纯暴力,从中间加

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e6 + 10;
    char s[N]; 
    int num[N], t[N], n;
    bool cmp() {
        for(int i = 1;i <= n; i++) {
            if(t[i] < num[i]) return true;
            else if(t[i] > num[i]) return false; 
        }
        return true;
    }
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%s", s+1);
            n = strlen(s+1);
            for (int i = 1; i <= n; i++) num[i] = s[i] - '0';
            for (int i = 1; i <= (n+1)/2; i++) {
                t[i] = t[n-i+1] = num[i];
            }
            if(n==1) {
                if(num[1] == 9) printf("11
    ");
                else printf("%d
    ", num[1]+1);
                continue;
            }
            while(cmp()) {
                t[(n+1)/2]++;
                for (int i = (n+1)/2; i >= 2; i--) {
                    t[i-1] += t[i]/10;
                    t[i] %= 10;
                }
                for (int i = 1; i <= (n+1)/2; i++) {
                    t[n-i+1] = t[i];
                }
            }
            for (int i = 1; i < n; i++) printf("%d", t[i]);
            if(t[n] == 10) printf("1
    ");//样例999 
            else printf("%d
    ", t[n]);
        }
        return 0;
    }
     
    View Code

     8002 树状数组区间更新,区间查询

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5;
    int a[N], n;
    LL sum[N], c1[N], c2[N];
    void add(int x, int a) {
        LL t = x;
        while(x <= n) c1[x] += a, c2[x] += t*a, x += x&-x;
    }
    LL query(int x) {
        LL ans = 0;
        LL t = x;
        while(x) ans += (t+1) * c1[x] - c2[x], x -= x&-x;
        return ans;
    }
    int main() {
        int T, op, c, p, q, v;
        scanf("%d", &T);
        while(T--) {
            mem(c1, 0);
            mem(c2, 0);
            scanf("%d%d", &n, &c);
            while(c--) {
                scanf("%d", &op);
                if(op == 1) {
                    scanf("%d%d", &p, &q);
                    printf("%lld
    ", query(q) - query(p-1));
                }
                else {
                    scanf("%d%d%d", &p, &q, &v);
                    add(p, v);
                    add(q+1, -v);
                }
            }
        }
        return 0;
    }
    View Code

    3267 离线+树状数组,每次保证这段区间每个数只更新一次,或者主席树(不会,等我学了在a)

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 3e5 + 5, M = 2e5 + 5;
    int a[N], nxt[N], bit[N], mp[M*5], n;
    struct node {
        int l, r, id;
        bool operator < (const node & t) const {
            if(l == t.l) return r < t.r;
            else return l < t.l;
        }
    }Q[M];
    int ans[N];
    void add(int x, int a) {
        while(x <= n) bit[x] += a, x += x&-x;
    }
    int query(int x) {
        int ans = 0;
        while(x) ans += bit[x], x -= x&-x;
        return ans;
    }
    int main() {
        int q;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
        for (int i = 1; i <= n; i++) {
            if(mp[a[i]] == 0) {
                add(i, 1);
                mp[a[i]] = i;
            }
        }
        mem(mp, 0);
        for (int i = n; i; i--) {
            if(mp[a[i]] == 0) {
                nxt[i] = n+1;
                mp[a[i]] = i;
            }
            else {
                nxt[i] = mp[a[i]];
                mp[a[i]] = i;
            }
        }
        scanf("%d", &q);
        for (int i = 0; i < q; i++) scanf("%d%d", &Q[i].l, &Q[i].r), Q[i].id = i;
        sort(Q, Q+q);
        int t = 1;
        for (int i = 0; i < q; i++) {
            while(t <= n && t < Q[i].l) add(nxt[t++], 1);
            ans[Q[i].id] = query(Q[i].r) - query(Q[i].l-1);
        }
        for (int i = 0; i < q; i++) printf("%d
    ", ans[i]);
        return 0;
    }
    View Code

    主席树(2019.3更新),感觉这个没有离线优秀,不过思想还行,就当练练可持久化

    #pragma GCC optimize(2)
    #pragma GCC optimize(3)
    #pragma GCC optimize(4)
    #include<iostream>
    #include<cstdio>
    #include<vector>
    #include<climits>
    using namespace std;
    #define y1 y11
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pli pair<LL, int>
    #define pii pair<int, int>
    #define piii pair<pii, int>
    #define pdd pair<double, double>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define debug(x) cerr << #x << " = " << x << "
    ";
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    //head
    
    const int N = 3e4 + 5, M = 1e6 + 5;
    int root[N], lson[M], rson[M], tree[M], tot = 0;
    void build(int &x, int l, int r) {
        x = ++tot;
        if(l == r) return ;
        int m = l+r >> 1;
        build(lson[x], l, m);
        build(rson[x], m+1, r);
        tree[x] = tree[lson[x]] + tree[rson[x]];
    }
    void update(int old, int &x, int p, int v, int l, int r) {
        x = ++tot;
        lson[x] = lson[old], rson[x] = rson[old], tree[x] = tree[old] + v;
        if(l == r) return ;
        int m = l+r >> 1;
        if(p <= m) update(lson[x], lson[x], p, v, l, m);
        else update(rson[x], rson[x], p, v, m+1, r);
    }
    int query(int L, int R, int x, int l, int r) {
        if(L <= l && r <= R) return tree[x];
        int m = l+r >> 1, ans = 0;
        if(L <= m) ans += query(L, R, lson[x], l, m);
        if(R > m ) ans += query(L, R, rson[x], m+1, r);
        return ans;
    }
    int n, a, mp[M], tmp, q, l, r;
    int main() {
        scanf("%d", &n);
        build(root[0], 1, n);
        for (int i = 1; i <= n; ++i) {
            scanf("%d", &a);
            if(mp[a]) {
                update(root[i-1], tmp, mp[a], -1, 1, n);
                update(tmp, root[i], i, 1, 1, n);
            }
            else update(root[i-1], root[i], i, 1, 1, n);
            mp[a] = i;
        }
        scanf("%d", &q);
        while(q--) {
            scanf("%d %d", &l, &r);
            printf("%d
    ", query(l, r, root[r], 1, n));
        }
        return 0;
    }
    View Code

    1437 树的直径,两遍dfs

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    vector<int>g[N];
    int mx = 0, ed = 0;
    void dfs(int o, int u, int st) {
        if(st > mx) {
            mx = st;
            ed = u;
        }
        for (int i = 0; i < g[u].size(); i++) {
            if(g[u][i] != o) {
                dfs(u, g[u][i], st+1);
            }
        }
    }
    int main() {
        int n, u, v;
        scanf("%d", &n);
        for (int i = 0; i < n-1; i++) {
            scanf("%d%d", &u, &v);
            g[u].pb(v);
            g[v].pb(u);
        }
        dfs(0, 1, 0);
        dfs(0, ed, 0);
        printf("%d
    ", mx);
        return 0;
    }
    View Code

    1436 dfs

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    vector<int>g[N];
    bool vis[N];
    bool f = true;
    void dfs(int o, int u) {
        vis[u] = true;
        for (int i = 0; i < g[u].size(); i++) {
            if(g[u][i] != o) {
                if(!vis[g[u][i]])dfs(u, g[u][i]);
                else f = false;
            }
        }
    }
    int main() {
        int n, m, u, v;
        scanf("%d%d", &n, &m);
        for (int i = 0; i < m; i++) {
            scanf("%d%d", &u, &v);
            g[u].pb(v);
            g[v].pb(u);
        }
        dfs(0, 1);
        for (int i = 1; i <= n; i++) if(!vis[i]) f = false;
        if(f) puts("YES");
        else puts("NO");
        return 0;
    }
    View Code

    6219  普通dp, 与LCS相似

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    char s[N], t[N];
    int dp[N][N];
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%s", s+1);
            scanf("%s", t+1);
            int n = strlen(s+1), m = strlen(t+1);
            for (int i = 0; i <= n; i++) {
                for (int j = 0; j <= m; j++) {
                    if(i||j){
                        if(i == 0) dp[i][j] = j;
                        else if(j == 0) dp[i][j] = i;
                        else if(s[i] == t[j]) dp[i][j] = dp[i-1][j-1];
                        else dp[i][j] = min(dp[i-1][j-1]+1, min(dp[i-1][j]+1, dp[i][j-1]+1));
                    }
                }
            }
            printf("%d
    ", dp[n][m]);
        }
        return 0;
    }
    View Code

     3923 普通dp

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 105;
    int a[N][N], dp[N][N];
    int main() {
        int T, n, m;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    scanf("%d", &a[i][j]);
                }
            }
            mem(dp, 0);
            for (int i = 1; i <= m; i++) dp[1][i] = a[1][i];
            for (int i = 2; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    dp[i][j] = max(dp[i-1][j], max(dp[i-1][j-1], dp[i-1][j+1])) + a[i][j];
                }
            }
            int ans = 0;
            for (int i = 1; i <= m; i++) ans = max(ans, dp[n][i]);
            printf("%d
    ", ans);
        }
        return 0;
    }
    View Code

     95 栈模拟

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    stack<int>s;
    int main() {
        int n, t;
        while(~scanf("%d", &n) && n) {
            while(!s.empty()) s.pop();
            int now = 1;
            for (int i = 1; i <= n; i++) {
                scanf("%d", &t);
                if(t == now) now++;
                else {
                    s.push(t);
                }
                while(!s.empty() && s.top() == now) {
                    s.pop();
                    now++;
                }
            }
            //cout << now << endl;
            if(now == n+1) puts("yes");
            else puts("no");
        }
        return 0;
    }
    View Code

    1021 原串与反串的LCS就是原串的最长回文子序列 

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 6e3 + 105;
    char s[N], t[N];
    int dp[N][N];
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%s", s+1);
            int n = strlen(s+1);
            for (int i = 1; i <= n; i++) t[i] = s[n-i+1];
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= n; j++) {
                    if(s[i] == t[j]) dp[i][j] = max(dp[i-1][j-1]+1, max(dp[i-1][j], dp[i][j-1]));
                    else dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
                }
            }
            printf("%d
    ", n-dp[n][n]);
        }
        return 0;
    }
    View Code

    14930 记忆化搜索

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    LL dp[N][2];
    int a[N], n;
    LL dfs(int pos, int sta) {
        if(pos == n) {
            if(sta == 0) return 0;
            else return a[n];
        }
        if(~dp[pos][sta]) return dp[pos][sta];
        if(sta == 1) return dp[pos][sta] = a[pos] + dfs(pos+1, 0);
        else return dp[pos][sta] = max(dfs(pos+1, 1), dfs(pos+1, 0));
    }
    int main() {
        int T;
        scanf("%d", &T);
        for (int cs = 1; cs <= T; cs++) {
            scanf("%d", &n);
            for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
            mem(dp, -1);
            LL ans = max(dfs(1, 0), dfs(1, 1));
            printf("Case %d: %lld
    ", cs, ans);
        }
        return 0;
    }
    View Code

    1841 bfs

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    bool notp[N];
    bool vis[N];
    int d[10], dd[10];
    int p[10] = {0, 1, 10, 100, 1000};
    int a, b, ans;
    bool bfs() {
        mem(vis, false);
        queue<pii>q;
        q.push(mp(a, 0));
        vis[a] = true;
        while(!q.empty()) {
            pii p = q.front();
            q.pop();
            int t = p.fi;
            if(t == b) {
                ans = p.se;
                return true;
            }
            for (int i = 1; i <= 4; i++) {
                d[i] = t%10;
                t /= 10;
            }
            for (int i = 1; i <= 4; i++) {
                int t = 0;
                if(i == 4) t = 1;
                for (int j = t; j < 10; j++) {
                    if(j == d[i]) continue;
                    for (int k = 1; k <= 4; k++) {
                        if(k == i) continue;
                        dd[k] = d[k];
                    }
                    dd[i] = j;
                    int n = 0;
                    for (int k = 4; k >=1; k--) n = n *10 + dd[k];
                    if(!notp[n] && !vis[n]) {
                        vis[n] = true;
                        q.push(mp(n, p.se+1));
                    }
                }
            }
        }
        return false;
    }
    int main() {
        int T;
        scanf("%d", &T);
        for (int i = 2; i < N; i++) {
            if(!notp[i]) {
                for (int j = i+i; j < N ;j += i) notp[j] = true;
            }
        }
        for (int cs = 1; cs <= T; cs++) {
            scanf("%d%d", &a, &b);
            if(bfs())printf("%d
    ", ans);
            else printf("Impossible
    ");
        }
        return 0;
    }
    View Code

    97 背包dp

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 555;
    int dp[N], c[N], v[N];
    int main() {
        int n, m;
        while(~scanf("%d%d", &n, &m)) {
            if(!n && !m) return 0;
            int ans;
            mem(dp, 0);
            for (int i = 1; i <= m; i++) scanf("%d%d", &c[i], &v[i]);
            for (int i = 1; i <= m; i++) {
                for (int j = n; j >= c[i]; j--) {
                    dp[j] = max(dp[j-c[i]]+v[i], dp[j]);
                }
            }
            for (int i = n; i >= 0; i--) if(dp[i] == dp[n]) ans = i;
            printf("%d %d
    ", ans, dp[n]);
        }
        return 0;
    }
    View Code

    740 区间dp, 小区间推大区间,dp[i][j] = max(dp[i+1][j] + (n+i-j) * a[i], dp[i][j-1] + (n+i-j) * a[j])

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    int dp[N][N], a[N];
    int main() {
        int n;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
        for (int i = n; i >=1; i--) {
            dp[i][i] = a[i] * n;
            for (int j = i+1; j <= n; j++) {
                dp[i][j] = max(dp[i+1][j] + (n+i-j) * a[i], dp[i][j-1] + (n+i-j) * a[j]);
            }
        }
        printf("%d
    ", dp[1][n]);
        return 0;
    }
    View Code

    206 每次向外扩展一次,做多扩展max(n,m)次,所以复杂度为max(n,m)*n*m

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 222;
    const int INF = 0x3f3f3f3f;
    char s[N][N]; 
    int ans[N][N];
    int dir[4][2] = {0, 1, 1, 0, 0, -1, -1, 0};
    int main() {
        int T, n, m;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            mem(ans, INF);
            for (int i = 1; i <= n; i++) scanf("%s", s[i]+1);
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    if(s[i][j] == '1') ans[i][j] = 0;
                }
            }
            for (int i = 1; i <= max(n, m); i++) {
                for (int j = 1; j <= n; j++) {
                    for (int k = 1; k <= m; k++) {
                        if(ans[j][k] != INF)
                        for (int l = 0; l < 4; l++) {
                            int x = j + dir[l][0];
                            int y = k + dir[l][1];
                            if(1 <= x && x <= n && 1 <= y && y <= m) {
                                ans[x][y] = min(ans[x][y], ans[j][k] + 1);
                            }
                        }
                    }
                }
            }
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    printf("%d%c", ans[i][j], " 
    "[j==m]);
                }
            }
        }
        return 0;
    }
    View Code

    9861 双指针

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 3e5 + 5;
    int a[N];
    int main() {
        int n, m;
        scanf("%d%d", &n, &m);
        for (int i = 1; i <= n; i++) {
            scanf("%d", &a[i]);
        }
        int ans = 0;
        int l = 0, r = 0, sum = 0;
        while(true) {
            while(sum <= m && r < n) {
                ans = max(ans, sum);
                sum += a[++r];
            }
            if(sum <= m) ans = max(ans, sum);
            while(sum > m) {
                sum -= a[++l];
            }
            if(sum <= m) ans = max(ans, sum);
            if(r == n) break;
        }
        printf("%d
    ", ans);
        return 0;
    }
    View Code

     3377 带权并查集或普通并查集

    带权

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    int fa[N], rnk[N];
    void init(int n) {
        for (int i = 0; i <= n; i++) {
            fa[i] = i;
            rnk[i] = 0;
        }
    }
    int find(int x) {
        if(fa[x] == x) return x;
        else{
            int tmp = fa[x];
            fa[x] = find(fa[x]);
            rnk[x] = (rnk[x] + rnk[tmp]) % 2;
            return fa[x];
        }
    }
    void merge(int x, int y) {
        int rx = find(x), ry = find(y);
        if(rx == ry) return;
        fa[rx] = ry;
        rnk[rx] = (rnk[y] + 1 -rnk[x]) % 2;
    }
    int main() {
        int T, n, m, u, v;
        scanf("%d", &T);
        for (int cs = 1; cs <= T; cs++) {
            scanf("%d%d", &n, &m);
            printf("Scenario #%d:
    ", cs);
            init(n);
            bool f = false;
            for (int i = 0; i < m; i++) {
                scanf("%d%d", &u, &v);
                if(find(u) == find(v) && rnk[u] == rnk[v]) f = true;
                else merge(u, v);
            }
            if(f) printf("Suspicious bugs found!
    ");
            else printf("No suspicious bugs found!
    ");
        }
        return 0;
    }
    View Code

    普通

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    int fa[N*2];
    void init(int n) {
        for (int i = 0; i <= n*2; i++) {
            fa[i] = i;
        }
    }
    int find(int x) {
        if(x == fa[x]) return x;
        else return fa[x] = find(fa[x]);
    }
    void merge(int x, int y) {
         int rx = find(x), ry = find(y);
         if(rx == ry) return;
         fa[rx] = ry;
    }
    int main() {
        int T, n, m, u, v;
        scanf("%d", &T);
        for (int cs = 1; cs <= T; cs++) {
            scanf("%d%d", &n, &m);
            printf("Scenario #%d:
    ", cs);
            init(n);
            bool f = false;
            for (int i = 0; i < m; i++) {
                scanf("%d%d", &u, &v);
                if(find(u) == find(v) || find(u+n) == find(v+n)) f = true;
                else merge(u, v+n), merge(v, u+n);
            }
            if(f) printf("Suspicious bugs found!
    ");
            else printf("No suspicious bugs found!
    ");
        }
        return 0;
    }
    View Code

    10582 multiset维护(注意删一个元素需要s.erase(s.find(x)),否则会把所有的x都会删掉),顺便复习了一下st表,用st表写了一发

    multiset

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e6 + 5;
    int a[N];
    multiset<int>s;
    int main() {
        int n, k;
        scanf("%d", &n);
        for (int i = 1; i <= n; ++i) scanf("%d", &a[i]);
        scanf("%d", &k);
        for (int i = 1; i < k; i++) s.insert(a[i]);
        for (int i = k; i <= n; i++) {
            s.insert(a[i]);
            auto it = s.end();
            it --;
            printf("%d%c", *it, " 
    "[i==n]);
            s.erase(s.find(a[i-k+1]));
        }
        return 0;
    }
    View Code

    st表

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e6 + 5;
    int a[N], st[N][20];
    int query(int l, int r) {
        int k = floor(log(r-l+1)/log(2));
        return max(st[l][k], st[r - (1 << k) + 1][k]);
    }
    int main() {
        int n, k;
        scanf("%d", &n);
        for (int i = 1; i <= n; ++i) scanf("%d", &a[i]);
        scanf("%d", &k);
        for (int i = n; i >= 1; i--) {
            st[i][0] = a[i];
            for (int j = 1; j + (1 << j-1) <= n; j++) {
                st[i][j] = max(st[i][j-1], st[i+(1 << j-1)][j-1]);
            }
        }
        for (int i = k; i <= n; i++) printf("%d%c", query(i-k+1, i), " 
    "[i==n]);
        return 0;
    }
    View Code

    4 stack

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    char s[N];
    bool is(char c) {
        if(c == '+' || c == '-' || c == '*' || c == '/' || c == '^') return true;
        else return false;
    }
    int main() {
        int T;
        scanf("%d", &T);
        while(T--) {
            scanf("%s", s+1);
            int n = strlen(s+1);
            stack<char>st;
            for (int i = 1; i <= n; i++) {
                if(isalpha(s[i])) putchar(s[i]);
                else if(is(s[i])) st.push(s[i]);
                else if(s[i] == ')') putchar(st.top()), st.pop();
            }
            puts("");
        }
        return 0;
    }
    View Code

    61 线段树区间合并,左区间的左括号和右区间的有括号抵消,看有没有剩下的没匹配的括号

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 3e4 + 5;
    char s[N];
    struct  sg_tree{
        int L[N<<2], R[N<<2];
        void push_up(int rt) {
            L[rt] = L[rt<<1] + L[rt<<1|1] - min(L[rt<<1], R[rt<<1|1]);
            R[rt] = R[rt<<1] + R[rt<<1|1] - min(L[rt<<1], R[rt<<1|1]);
        }
        void build(int rt, int l,int r) {
            if(l == r) {
                if(s[l] == '(') L[rt] = 1, R[rt] = 0;
                else R[rt] = 1, L[rt] = 0;
                return ;
            }
            int m = (l+r) >> 1;
            build(ls);
            build(rs);
            push_up(rt);
        }
        void update(int p, int rt, int l, int r) {
            if(l == r) {
                L[rt] ^= 1;
                R[rt] ^= 1;
                return ;
            }
            int m = (l+r) >> 1;
            if(p <= m) update(p, ls);
            else update(p, rs);
            push_up(rt);
        }
    }sg;
    
    int main() {
        int n, m, t, cs = 0;
        while(~ scanf("%d", &n)) {
            scanf("%s", s+1);
            scanf("%d", &m);
            printf("Test %d:
    ", ++cs);
            sg.build(1, 1, n);
            while(m--) {
                scanf("%d", &t);
                if(!t) {
                    if(sg.L[1] || sg.R[1]) printf("NO
    ");
                    else printf("YES
    ");
                }
                else sg.update(t, 1, 1, n);
            }
        }
        return 0;
    }
    View Code

    1716 线段树区间合并,同1043

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 5e4 + 5;
    const int INF = 0x7f7f7f7f;
    struct Tree {
        int sum, lv, rv, ans;
    }tree[N<<2];
    void push_up(int rt) {
        tree[rt].sum = tree[rt<<1].sum + tree[rt<<1|1].sum;
        tree[rt].lv = max(tree[rt<<1].lv, tree[rt<<1].sum + tree[rt<<1|1].lv);
        tree[rt].rv = max(tree[rt<<1|1].rv, tree[rt<<1|1].sum + tree[rt<<1].rv);
        tree[rt].ans = max(tree[rt<<1].rv + tree[rt<<1|1].lv, max(tree[rt<<1].ans, tree[rt<<1|1].ans));
    }
    void build(int rt, int l, int r) {
        if(l == r) {
            scanf("%d", &tree[rt].ans);
            tree[rt].lv = tree[rt].rv = tree[rt].sum = tree[rt].ans;
            return ;
        }
        int m = (l+r) >> 1;
        build(ls);
        build(rs);
        push_up(rt);
    }
    void update(int p, int x, int rt, int l ,int r) {
        if(l == r) {
            tree[rt].lv = tree[rt].rv = tree[rt].sum = tree[rt].ans = x;
            return ;
        }
        int m = (l+r) >> 1;
        if(p <= m) update(p, x, ls);
        else update(p, x, rs);
        push_up(rt);
    }
    Tree query(int L, int R, int rt, int l, int r) {
        if(L <= l && r <= R) return tree[rt];
        int m = (l + r) >> 1;
        if(R <= m) return query(L, R, ls);
        else if(L > m) return query(L, R, rs);
        Tree lft = query(L, R, ls);
        Tree rit = query(L, R, rs);
        int sum = lft.sum+rit.sum;
        int lv = max(lft.lv, lft.sum+rit.lv);
        int rv = max(rit.rv, rit.sum+lft.rv);
        int ans = max(lft.rv+rit.lv, max(lft.ans, rit.ans));
        return Tree{sum, lv, rv, ans};
    }
    int main() {
        int n, m, x, y, op;
        scanf("%d", &n);
        build(1, 1, n);
        scanf("%d", &m);
        while(m --) {
            scanf("%d%d%d", &op, &x, &y);
            if(op) {
                Tree res = query(x, y, 1, 1, n);
                printf("%d
    ", res.ans);
            }
            else {
                update(x, y, 1, 1, n);
            }
        }
        return 0;
    }
    View Code

    345 区间dp,经典石子归并问题

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 105;
    const int INF = 0x3f3f3f3f;
    int a[N], sum[N], dp[N][N];
    int main() {
        int n;
        while(~scanf("%d", &n)) {
            for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
            for (int i = 1; i <= n; i++) sum[i] = sum[i-1] + a[i];
            for (int l = 2; l <= n; l ++) {
                for (int i = 1; i+l-1 <= n; i++) {
                    int j = i+l-1;
                    dp[i][j] = INF;
                    for (int k = i; k < j; k++) {
                        dp[i][j] = min(dp[i][j], dp[i][k] + dp[k+1][j] + ((sum[k]-sum[i-1])%100) * ((sum[j]-sum[k])%100));
                    }
                }
            }
            printf("%d
    ", dp[1][n]);
        } 
        return 0;
    }
    View Code

    4580 折半枚举

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0) 
    #define LL long long 
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int> 
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 105, M = 1e6 + 10;
    int a[N], b[M];
    int main() {
        int n;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
        int cnt = 0;
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= n; j++) {
                for (int k = 1; k <= n; k++) {
                    b[++cnt] = a[i] * a[j] + a[k];
                }
            }
        }
        sort(b+1, b+1+cnt);
        LL ans = 0;
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= n; j++) {
                for (int k = 1; k <= n; k++) {
                    if(a[i] != 0) {
                        int t1 = lower_bound(b+1, b+1+cnt, a[i]*(a[j]+a[k])) - b;
                        int t2 = upper_bound(b+1, b+1+cnt, a[i]*(a[j]+a[k])) - b;
                        ans += t2-t1;
                    }
                }
            }
        }
        printf("%d
    ", ans);
        return 0;
    }
    View Code

    302 数学

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<vector>
    #include<algorithm>
    #include<cmath>
    #include<vector>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    int main() {
        int T, n;
        scanf("%d", &T);
        while(T--) {
            scanf("%d", &n);
            int nn = n;
            int t = sqrt(2*n);
            t++;
            if(t*(t-1)/2 >= n) t--;
            n -= t*(t-1)/2;
            if(t%2==0)printf("TERM %d IS %d/%d
    ", nn, n, t-n+1);
            else printf("TERM %d IS %d/%d
    ", nn, t-n+1, n);
        }
        return 0;
    }
    View Code

    423 状压dp,一开始写了个n*n*(1<<n),后来发现每次不用枚举每个状态,只需枚举到上一行为止的所有状态就可以了,开个二维vector滚动保存状态,暴力水过?

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 22;
    LL dp[(1<<20) + 5][N];
    int a[N][N];
    bool vis[(1<<20) + 5];
    vector<int>sta[2];
    int main() {
        int T, n;
        scanf("%d", &T);
        while(T--) {
            scanf("%d", &n);
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= n; j++) scanf("%d", &a[i][j]);
            }
            mem(dp, 0);
            dp[0][0] = 1;
            int cur = 0;
            sta[0].clear();
            sta[1].clear();
            sta[cur].pb(0);
            for (int i = 1; i <= n; i++) {
                cur ^= 1;
                sta[cur].clear();
                mem(vis, false);
                for (int j = 1; j <= n; j++) {
                    if(a[i][j]) {
                        for (int k = 0; k < sta[1-cur].size(); k++) {
                            if(!(sta[1-cur][k] & (1 << (j-1)))) {
                                dp[sta[1-cur][k]|(1 << (j-1))][i] += dp[sta[1-cur][k]][i-1];
                                if(!vis[sta[1-cur][k]|(1 << (j-1))])sta[cur].pb(sta[1-cur][k]|(1 << (j-1))), vis[sta[1-cur][k]|(1 << (j-1))] = true;
                            }
                        }
                    }
                }
            }
            printf("%lld
    ", dp[(1<<n)-1][n]);
        }
        return 0;
    }
    View Code

    3266 离线+树状数组,先按询问的k排序,然后把从大到小(我的代码是从小到大,求的是小于等与k的)加入这些数的位置,然后只需要维护前缀和就可以了

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 3e4 + 5, M = 2e5 + 5;
    int id[N], a[N], bit[N], ans[M], n;
    struct node {
        int l, r, k, id;
        bool operator < (const node & t) const {
            return k < t.k;
        }
    }b[M];
    bool cmp(int x, int y) {
        return a[x] < a[y];
    }
    void add(int x, int a) {
        while(x <= n) bit[x] += a, x += x&-x;
    }
    int query(int x) {
        int ans = 0;
        while(x) ans += bit[x], x -= x&-x;
        return ans;
    }
    int main() {
        int q;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++) scanf("%d", &a[i]), id[i] = i;
        scanf("%d", &q);
        for (int i = 1; i <= q; i++) scanf("%d%d%d", &b[i].l, &b[i].r, &b[i].k), b[i].id = i;
        sort(b+1, b+1+q);
        sort(id+1, id+1+n, cmp);
        int t = 1;
        for (int i = 1; i <= q; i++) {
            while(t <= n && a[id[t]] <= b[i].k) add(id[t], 1), t++;
            ans[b[i].id] = b[i].r - b[i].l + 1 - query(b[i].r) + query(b[i].l-1);
        }
        for (int i = 1; i <= q; i++) printf("%d
    ", ans[i]);
        return 0;
    }
    View Code

    3946 线段树每个节点开个vector, 然后二分求区间第k大,单次询问复杂度(logn)^3,二分一个logn,线段树一个logn,每个节点二分一个logn

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5;
    int a[N];
    vector<int>vc[N<<2];
    vector<int>node;
    void build(int rt, int l, int r) {
        if(l == r) {
            scanf("%d", &a[l]);
            vc[rt].pb(a[l]);
            return ;
        }
        int m = (l+r) >> 1;
        build(ls);
        build(rs);
        for (int i = l; i <= r; i++) vc[rt].pb(a[i]);
        sort(vc[rt].begin(), vc[rt].end());
    }
    void query(int L, int R, int rt, int l, int r) {
        if(L <= l && r <= R) {
            node.pb(rt);
            return ;
        }
        int m = (l+r) >> 1;
        if(L <= m) query(L, R, ls);
        if(R > m) query(L, R, rs);
    }
    int cal(int x) {
        int ans = 0;
        for (int i = 0; i < node.size(); i++) {
            ans += lower_bound(vc[node[i]].begin(), vc[node[i]].end(), x) - vc[node[i]].begin();
        }
        return ans;
    }
    int main() {
        int n, m, l, r, k;
        scanf("%d%d", &n, &m);
        build(1, 1, n);
        sort(a+1, a+1+n);
        while(m--) {
            scanf("%d%d%d", &l, &r, &k);
            node.clear();
            query(l, r, 1, 1, n);
            l = 1, r = n;
            int md = (l+r+1) >> 1;
            while(l < r) {
                int cnt = cal(a[md]);
                if(cnt < k) l = md;
                else r = md - 1;
                md = (l+r+1) >> 1;
            }
            printf("%d
    ", a[md]);
        }
        return 0;
    }
    View Code

    16487 差分数组

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e4 + 5;
    int a[N];
    int main() {
        int T, n, m, q, v, l, r;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &m);
            mem(a, 0);
            for (int i = 1; i <= m; i++) scanf("%d%d%d", &l, &r, &v), l++, r++, a[l] += v, a[r+1] -= v;
            for (int i = 1; i <= n; i++) a[i] += a[i-1];
            scanf("%d", &q);
            for (int i = 1; i <= q; i++) scanf("%d", &l), printf("%d
    ", a[l+1]);
        }
        return 0;
    }
    View Code

    4300 暴力水题

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    int main() {
        int n;
        scanf("%d", &n);
        int ans = 0;
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j * j <= i; j++) {
                if(i%j == 0) ans++;
            }
        }
        printf("%d
    ", ans);
        return 0;
    }
    View Code

    14932 lca水题

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e3 + 5;
    int anc[N][15], deep[N];
    vector<int>g[N];
    bool vis[N];
    void dfs(int o, int u) {
        deep[u] = deep[o] + 1;
        for (int i = 0; i < g[u].size(); i++) {
            anc[g[u][i]][0] = u;
            for (int j = 1; j < 15; j++) anc[g[u][i]][j] = anc[anc[g[u][i]][j-1]][j-1];
            dfs(u, g[u][i]);
        }
    }
    int lca(int u, int v) {
        if(deep[u] > deep[v]) swap(u, v);
        for (int i = 14; i >= 0; i--) if(deep[anc[v][i]] >= deep[u]) v = anc[v][i];
        if(u == v) return u;
        for (int i = 14; i >= 0; i--) if(anc[u][i] != anc[v][i]) u = anc[u][i], v= anc[v][i];
        return anc[u][0];
    }
    int main() {
        int T, n, t, u, v, m;
        scanf("%d", &T);
        for (int cs = 1; cs <= T; cs++) {
            mem(vis, false);
            mem(deep, 0);
            scanf("%d", &n);
            for (int i = 1; i <= n; i++) g[i].clear();
            for (int i = 1; i <= n; i++) {
                scanf("%d", &t);
                while(t--) scanf("%d", &u), vis[u] = true, g[i].pb(u);
            }
            int rt = 0;
            for (int i = 1; i <= n; i++) if(!vis[i]) rt = i;
            dfs(0, rt);
            scanf("%d", &m);
            printf("Case %d:
    ", cs);
            while(m--) {
                scanf("%d%d", &u, &v);
                printf("%d
    ", lca(u, v));
            }
        }
        return 0;
    }
    View Code

    32 kmp 或者 字符串hash

    kmp

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e6 + 5;
    const int MOD = 1e9 + 7;
    int nxt[N];
    char a[N], b[N];
    vector<int>ans;
    int main() {
        int n, m;
        while(~scanf("%d", &n)){
            scanf("%s", a);
            scanf("%s", b);
            m = strlen(b);
            nxt[0] = -1;
            for (int i = 1; i < n; i++) {
                int j = nxt[i-1];
                while(a[j+1] != a[i] && j >= 0) j = nxt[j];
                if(a[j+1] == a[i]) nxt[i] = j+1;
                else nxt[i] = -1;
    
            }
            int i = 0, j = 0;
            ans.clear();
            while(j < m) {
                if(b[j] == a[i]) {
                    i++;
                    j++;
                    if(i == n) ans.pb(j - n), i = nxt[i-1]+1;
                }
                else {
                    if(i == 0) j++;
                    else i = nxt[i-1]+1;
                }
            }
            if(ans.size() == 0) puts("");
            else {
                for (int i = 0; i < ans.size(); i++) printf("%d
    ", ans[i]);
            }
        }
        return 0;
    }
    View Code

    字符串hash

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e6 + 5;
    const int MOD = 1e9 + 7;
    const int base = 23;
    char a[N], b[N];
    int H[N], p[N];
    int get_H(int l, int r) {
        return (H[r] - 1LL * H[l-1] * p[r-l+1] % MOD + MOD)%MOD;
    }
    vector<int>ans;
    int main() {
        int n, m;
        p[0] = 1;
        for (int i = 1; i < N; i++)p[i] = (1LL * p[i-1] * base)%MOD;
        while(~scanf("%d", &n)){
            scanf("%s", a+1);
            int f = 0;
            for (int i = 1; i <= n; i++) f = (1LL * f * base + a[i] - 'a')%MOD;
            scanf("%s", b+1);
            m = strlen(b+1);
            for (int i = 1; i <= m; i++) H[i] = (1LL * H[i-1] * base + (b[i] - 'a'))%MOD;
            ans.clear();
            for (int i = 1; i+n-1 <= m; i++) {
                if(get_H(i, i+n-1) == f) ans.pb(i);
            }
            if(ans.size() == 0) puts("");
            else {
                for (int i = 0; i < ans.size(); i++) printf("%d
    ", ans[i]-1);
            }
        }
        return 0;
    }
    View Code

     11

    我的傻逼写法:离线+指针,复杂度:Maxa * log(a) + n

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5;
    pii Q[N];
    int ans[N];
    int main() {
        int T;
        scanf("%d", &T);
        for (int i = 1; i <= T; i++) scanf("%d", &Q[i].fi), Q[i].se = i;
        sort(Q+1, Q+1+T);
        int l = 0, c2 = 0, c5 = 0;
        for (int i = 1; i <= T; i++) {
            while(l < Q[i].fi) {
                l++;
                int t = l;
                while(t%2 == 0) c2++, t /= 2;
                while(t%5 == 0) c5++, t /= 5;
            }
            ans[Q[i].se] = min(c2, c5);
        }
        for (int i = 1; i <= T; i++) printf("%d
    ", ans[i]);
        return 0;
    }
    View Code

    正解:数学

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    int main() {
        int T, n;
        scanf("%d", &T);
        for (int i = 1; i <= T; i++) {
            scanf("%d", &n);
            int ans = 0;
            for (LL i = 5; i <= n; i *= 5) ans += n/i;
            printf("%d
    ", ans);
        }
        return 0;
    }
    View Code

    7742 水题

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    //#define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 5e5 + 5;
    int a[N];
    int main() {
        int n;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
        sort(a+1, a+1+n);
        int c = 0;
        for (int i = 1; i <= n; i++) {
            if(a[i] != a[i-1]) {
                if(c == 1) return 0 * printf("%d
    ", a[i-1]);
                c = 1;
            }
            else c++;
        }
        if(c == 1) printf("%d
    ", a[n]);
        return 0;
    }
    View Code

    54 java大数

    import java.math.*;
    import java.util.*;
    
    public class Main {
        public static void main(String[] args) {
            Scanner reader = new Scanner(System.in);
            BigInteger d = new BigInteger("2");
            while(reader.hasNext()){
                BigInteger a = reader.nextBigInteger();
                BigInteger b = reader.nextBigInteger();
                BigInteger c = a.subtract(b);
                c = c.divide(d);
                System.out.println(c.add(b));
                System.out.println(c);
            }
        }
    }
    View Code

    3442 快速幂

    #include<bits/stdc++.h>
    using namespace std;
    #define LL long long
    LL q_pow(LL n, LL k) {
        LL ans = 1;
        while(k) {
            if(k&1) ans = (ans * n) % 10;
            n = (n*n) % 10;
            k >>= 1;
        }
        return ans;
    }
    int main() {
        int T;
        LL a, b;
        scanf("%d", &T);
        while(T--) {
            scanf("%lld%lld", &a, &b);
            printf("%lld
    ", q_pow(a, b));
        }
        return 0;
    }
    View Code

    11515 贪心,每次取这个位置之后能达到的最近的位置,先把每个l和r标记为a[l] = r,然后求个后缀最小值,预处理或者树状数组都可以

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 1e5 + 5, M = 1e6 + 5;
    const int INF = 0x3f3f3f3f;
    pii a[N];
    int b[M], bit[M];
    int mx;
    void add(int x, int a) {
        while(x) bit[x] = min(bit[x], a), x -= x&-x;
    }
    int query(int x) {
        int ans = INF;
        while(x <= mx) ans = min(ans, bit[x]), x += x&-x;
        return ans;
    }
    int main() {
        int T, n;
        scanf("%d", &T);
        while(T--) {
            scanf("%d", &n);
            mx = 0;
            for (int i = 1; i <= n; i++) scanf("%d%d", &a[i].fi, &a[i].se), a[i].fi++, a[i].se++, mx = max(mx, a[i].se);
            //sort(a+1, a+1+n);
            mem(b, INF);
            mem(bit, INF);
            for (int i = 1; i <= n; i++) b[a[i].fi] = min(b[a[i].fi], a[i].se);
            for (int i = 1; i < mx; i ++) {
                if(b[i] != INF) add(i, b[i]); //cout << i << " " << b[i] << endl;
            }
            int st = 1, ans = 0;
            while(st <= mx) {
                st = query(st);
                if(st == INF) break;
                else ans++;
            }
            printf("%d
    ", ans);
        }
        return 0;
    }
    View Code

    39 完全背包

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 555, M = 1e4 + 10;
    const int INF = 0x3f3f3f3f;
    pii a[N];
    int dp[M];
    int main() {
        int T, n, e, f, w;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &e, &f);
            scanf("%d", &n);
            for (int i = 1; i <= n; i++)scanf("%d%d", &a[i].fi, &a[i].se);
            mem(dp, INF);
            dp[0] = 0;
            w = f - e;
            for (int i = 1; i <= n; i++) {
                for (int j = a[i].se; j <= w; j++) {
                    dp[j] = min(dp[j], dp[j-a[i].se]+a[i].fi);
                }
            }
            if(dp[w] == INF) printf("This is impossible.
    ");
            else printf("The minimum amount of money in the piggy-bank is %d.
    ", dp[w]);
        }
        return 0;
    }
    View Code

    3273 离散化+树状数组+二分

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e5 + 5;
    pair<int, char> Q[N];
    int a[N], bit[N], cnt[N], q;
    char s[10];
    void add(int x, int a) {
        while(x <= q) bit[x] += a, x += x&-x;
    }
    int query(int x) {
        int ans = 0;
        while(x) ans += bit[x], x -= x&-x;
        return ans;
    }
    int MP[N];
    int main() {
        int t;
        scanf("%d", &q);
        for (int i = 1; i <= q; i++) {
            scanf("%s%d", s, &t);
            Q[i] = mp(t, s[0]);
            a[i] = t;
        }
        sort(a+1, a+1+q);
        for (int i = 1; i <= q; i++) {
            t = lower_bound(a+1, a+1+q, Q[i].fi) - a;
            if(Q[i].se != 'K') {
                MP[t] = Q[i].fi;
                Q[i].fi = t;
            }
        }
        for (int i = 1; i <= q; i++) {
            if(Q[i].se == 'I') {
                if(!cnt[Q[i].fi])add(Q[i].fi, 1), cnt[Q[i].fi]++;
            }
            else if(Q[i].se == 'D') {
                if(cnt[Q[i].fi]) cnt[Q[i].fi]--, add(Q[i].fi, -1);
            }
            else if(Q[i].se == 'K') {
                if(Q[i].fi > query(q)) {
                    printf("invalid
    ");
                    continue;
                }
                int l = 1, r = q, m = (l+r) >> 1;
                while(l < r) {
                    if(query(m) < Q[i].fi) l = m+1;
                    else r = m;
                    m = (l+r) >> 1;
                }
                printf("%d
    ", MP[m]);
            }
            else if(Q[i].se == 'C') {
                printf("%d
    ", query(Q[i].fi-1));
            }
        }
        return 0;
    }
    View Code

    5449 stack

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    char s[N];
    int main() {
        int cs = 0;
        while(~scanf("%s", s+1)) {
            if(s[1] == '-') break;
            int n = strlen(s+1);
            int l = 0, ans = 0;
            for (int i = 1; i <= n; i++) {
                if(s[i] == '{') l++;
                else {
                    if(l) l--;
                    else ans++, l++;
                }
            }
            ans += l/2;
            printf("%d. %d
    ", ++cs, ans);
        }
        return 0;
    }
    View Code

    12471 dp+记忆化搜索

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 2e3 + 5;
    int dp[N][N][3];
    int dir[3][2] = {3, 2, -5, -10, -20, 5};
    int dfs(int a, int b, int t) {
        if(a <= 0 || b <= 0) return -1;
        if(~dp[a][b][t]) return dp[a][b][t];
        for (int i = 0; i < 3; i++) {
            if(i != t)dp[a][b][t] = max(dp[a][b][t], dfs(a+dir[i][0], b+dir[i][1], i)+1);
        }
        return dp[a][b][t];
    }
    int main() {
        int T, h, a;
        mem(dp, -1);
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &h, &a);
            printf("%d
    ", max(max(dfs(h, a, 0), dfs(h, a, 1)), dfs(h, a, 0)));
        }
        return 0;
    }
    View Code

    24 java大数

    import java.math.*;
    import java.util.*;
    
    public class Main {
        public static void main(String[] args) {
            Scanner reader = new Scanner(System.in);
            int t;
            long n;
            t = reader.nextInt();
            for (int i = 1; i <= t; i++) {
                n = reader.nextLong();
                BigInteger ans = new BigInteger("1");
                for (long j = 1; j <= n; j++) {
                    ans = ans.multiply(BigInteger.valueOf(j));
                }
                System.out.println(ans);
            }
        }
    }
    View Code

    9921 bfs水题

    #include<bits/stdc++.h>
    using namespace std;
    #define fi first
    #define se second
    #define pi acos(-1.0)
    #define LL long long
    #define mp make_pair
    #define pb push_back
    #define ls rt<<1, l, m
    #define rs rt<<1|1, m+1, r
    #define ULL unsigned LL
    #define pll pair<LL, LL>
    #define pii pair<int, int>
    #define piii pair<int,pii>
    #define mem(a, b) memset(a, b, sizeof(a))
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("in.txt", "r", stdin);freopen("out.txt", "w", stout);
    //head
    
    const int N = 55;
    char s[N][N];
    bool vis[N][N];
    int n, m;
    int dir[8][2] = {1, 0, 0, 1, -1, 0, 0, -1, 1, -1, -1, 1, 1, 1, -1, -1};
    queue<piii>q;
    int main() {
        int cs = 0;
        while(~scanf("%d%d", &n, &m)) {
            if(!n && !m) break;
            for (int i = 1; i <= n; i++) scanf("%s", s[i]+1);
            mem(vis, false);
            for (int i = 1; i <= n; i++) {
                for (int j = 1; j <= m; j++) {
                    if(s[i][j] == 'A') {
                        q.push({1, {i, j}});
                        vis[i][j] = true;
                    }
                }
            }
            int ans = 0;
            while(!q.empty()) {
                piii p = q.front();
                q.pop();
                ans = p.fi;
                for (int i = 0; i < 8; i++) {
                    int x = p.se.fi + dir[i][0];
                    int y = p.se.se + dir[i][1];
                    if(1 <= x && x <= n && 1 <= y && y <= m && !vis[x][y] && s[x][y] == s[p.se.fi][p.se.se]+1) {
                        vis[x][y] = true;
                        ans = p.fi + 1;
                        q.push({p.fi+1, {x, y}});
                    }
                }
            }
            printf("Case %d: %d
    ", ++cs, ans);
        }
        return 0;
    }
    View Code

    总结1:按点赞数降序第一页都是水题,不过复习了之前学过的算法(线段树合并、区间dp之类的),学会了各种离线操作,所以不打算刷简单题了。

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  • 原文地址:https://www.cnblogs.com/widsom/p/9068570.html
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